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rosijanka [135]
3 years ago
6

How many moles are equal to 89.23 g of calcium nitrate?

Chemistry
1 answer:
DanielleElmas [232]3 years ago
6 0

Answer:

23

Explanation:

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What is the product(s) of the reaction below?
Lesechka [4]

Answer:

is b

Explanation:

es la b porque estpy estudiando lo mismo

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3 years ago
A drink is made up mostly of water. A small amount of sweet powder is stirred in using a spoon. The power in this solution is th
Helen [10]
Well the solvent is the liquid in a solution so your answer would be Solute, D. That is the one that would represent the sugar crystals being evenly mixed into a solution.
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3 years ago
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Which of the following will be most soluble in octane?
natima [27]

Answer:

CH3CH3CH2CH3

Explanation:

Octane is a non-polar compound. It is a hydrocarbon with 8-carbon length along its chain.

It belongs to a special group of hydrocarbons called alkanes.

What makes a substance soluble in another?

   It is a common phrase that  "like dissolves like". This is applicable to solubility of substances in another.

  • A polar solvent will freely and easily dissolve a polar solute. For example, water and salt.
  • A non-polar solvent will also dissolve a non-polar solute. This case, hydrocarbons will dissolve themselves.
  • The first option is a butane, a 4-carbon length hydrocarbon which will be dissolved in octane.
  • Both compounds are non-polar.
7 0
3 years ago
What mass of sodium chloride is needed to prepare 200 ml of a 0.1 M solution
Nikolay [14]

Answer:

C. 1.17 grams

Explanation:

  • The molarity is the no. of moles of solute in a 1.0 L of the solution.

<em>M = (mass/molar mass)solute x (1000/ V)</em>

M = 0.1 M, mass = ??? g, molar mass of NaCl = 58.44 g/mol, V = 200.0 mL.

∴ mass of NaCl = (M)(molar mass)(V)/1000 = (0.1 M)(58.44 g/mol)(200.0 mL)/1000 = 1.168 g ≅ 1.17 g.

5 0
3 years ago
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A rigid tank contains 1.40 moles of an ideal gas. Determine the number of moles of gas that must be withdrawn from the tank to l
sergey [27]

Answer : The final number of moles of gas that withdrawn from the tank to lower the pressure of the gas must be, 0.301 mol.

Explanation :

As we know that:

PV=nRT

At constant volume and temperature of gas, the pressure will be directly proportional to the number of moles of gas.

The relation between  pressure and number of moles of gas will be:

\frac{P_1}{P_2}=\frac{n_1}{n_2}

where,

P_1 = initial pressure of gas = 24.5 atm

P_2 = final pressure of gas = 5.30 atm

n_1 = initial number of moles of gas = 1.40 moles

n_2 = final number of moles of gas = ?

Now put all the given values in the above expression, we get:

\frac{24.5atm}{5.30atm}=\frac{1.40mol}{n_2}

n_2=0.301mol

Therefore, the final number of moles of gas that withdrawn from the tank to lower the pressure of the gas must be, 0.301 mol.

8 0
3 years ago
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