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earnstyle [38]
2 years ago
5

Does the tide that the moon raises on the earth different?

Physics
1 answer:
alukav5142 [94]2 years ago
7 0

Answer:

No the gravity of the moon pulls the water making high tide

Explanation:

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Free falling objects accelerate at 9.8 m/s because the force of
Gala2k [10]
The answer is
B. Gravity
6 0
3 years ago
Examples of motor and generator?​
Dafna11 [192]

Hope this helps

Answer:In a generator, current is produced in the armature winding. Ceiling fans, cars, etc. are all examples of motor. In power stations, generator is used to generate electricity.

6 0
2 years ago
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A man runs at 7.5 m s-1 due east across the deck of a ship which moves at 10.0 m s-1 due north. Determine the resultant velocity
german

Answer:

12.5 m/s North/east

Explanation:

I thought of it as a graph. I basically just found the distance between the points (0,0) and (10, 7.5)!

7 0
3 years ago
If an object on a spring became four times as massive, how would that affect the period of its oscillation on the spring?
pentagon [3]
The formula for the time period oscillation of a spring is:
T = 2π√(m/k) where m is the mass of the object attached to the spring and k is the spring constant of the spring.

Multiplying m by 4 we have:
2π√(4m/k)
= 2π x 2√(m/k)
or 2 x (2π√(m/k)) or 2T.

Therefore, when object is four times as massive, then period will double.
6 0
3 years ago
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A spring stretches 0.1 m when a 0.5 kg mass is hung from it. The spring is now oriented horizontally with the mass attached to o
monitta

Answer:

1.98 rad/s

Explanation:

Given that a spring stretches at a distance x_0  0.1 m when a mass of 0.5 kg is attached to it.

The angular velocity w = \sqrt {\frac{k}{m}} = \sqrt{\frac{g}{x_0}}

\omega = \sqrt{\frac{g}{x_0}}\\\\\omega = \sqrt{\frac{9.81}{0.1}}\\\\\omega = 9.9 \ rad/s

If it is stretched 0.2 m from the equilibrium length; we have:

The maximum velocity v = 0.2 × 9.9

v = 1.98 rad/s

Therefore; the maximum velocity of the mass =  1.98 rad/s

5 0
3 years ago
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