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earnstyle [38]
3 years ago
5

Does the tide that the moon raises on the earth different?

Physics
1 answer:
alukav5142 [94]3 years ago
7 0

Answer:

No the gravity of the moon pulls the water making high tide

Explanation:

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who needs more friends on here go to my profile and hit thank you button and friend request and whoever do it first get brianlis
qwelly [4]

Answer:

BET SHORTY

Explanation:

THX

7 0
3 years ago
Read 2 more answers
A model rocket rises with constant acceleration to a height of 4.2 m, at which point its speed is 27.0 m/s. How much time does i
geniusboy [140]

Answers:

a) t=0.311 s

b) a=86.847 m/s^{2}

c) y=1.736 m

d) V=17.369 m/s

Explanation:

For this situation we will use the following equations:

y=y_{o}+V_{o}t+\frac{1}{2}at^{2} (1)  

V=V_{o} + at (2)  

Where:  

y is the <u>height of the model rocket at a given time</u>

y_{o}=0 is the i<u>nitial height </u>of the model rocket

V_{o}=0 is the<u> initial velocity</u> of the model rocket since it started from rest

V is the <u>velocity of the rocket at a given height and time</u>

t is the <u>time</u> it takes to the model rocket to reach a certain height

a is the <u>constant acceleration</u> due gravity and the rocket's thrust

<h2>a) Time it takes for the rocket to reach the height=4.2 m</h2>

The average velocity of a body moving at a constant acceleration is:

V=\frac{V_{1}+V_{2}}{2} (3)

For this rocket is:

V=\frac{27 m/s}{2}=13.5 m/s (4)

Time is determined by:

t=\frac{y}{V} (5)

t=\frac{4.2 m}{13.5 m/s} (6)

Hence:

t=0.311 s (7)

<h2>b) Magnitude of the rocket's acceleration</h2>

Using equation (1), with initial height and velocity equal to zero:

y=\frac{1}{2}at^{2} (8)  

We will use y=4.2 m :

4.2 m=\frac{1}{2}a(0.311)^{2} (9)  

Finding a:

a=86.847 m/s^{2} (10)  

<h2>c) Height of the rocket 0.20 s after launch</h2>

Using again y=\frac{1}{2}at^{2} but for t=0.2 s:

y=\frac{1}{2}(86.847 m/s^{2})(0.2 s)^{2} (11)

y=1.736 m (12)

<h2>d) Speed of the rocket 0.20 s after launch</h2>

We will use equation (2) remembering the rocket startted from rest:

V= at (13)  

V= (86.847 m/s^{2})(0.2 s) (14)  

Finally:

V=17.369 m/s (15)  

5 0
3 years ago
An objects speed is 2.40 m/s, and its momentum is 120.0 kg m/s. what is the mass of the object?
jarptica [38.1K]
Momentum is defined as 

P = m*v

where m is the mass of the object
and v is the speed of the object

We find m.............> m = P/v = 120 [kg.m/s] / 2.4 [m/s] = 50 kg

The mass is 50 kg
4 0
4 years ago
What are the basic si units for the wavelength of light?
noname [10]

Answer:

Meter (m)

Explanation:

The wavelenght of a light wave is a measure of the distance between two successive crests (or two successive troughs) of a light wave.

Since the SI units for the distance is the meter (m), then the SI unit for the wavelength is also the meter (m).

Wavelength is related to the frequency of the light wave by:

\lambda=\frac{c}{f}

where

c is the speed of light

f is the frequency of the light

7 0
3 years ago
A 78-kg skydiver has a speed of 62 m/s , what is the kinetic energy?​
Cloud [144]

Answer:

149,916J

Explanation:

Pneumonic device: Kevin is half-mad and very square

this translates to: KE=(1/2)mv^2 !!

KE=(1/2)(78)(62^2)

KE=(39)(3844)

KE=149,916 Joules

3 0
3 years ago
Read 2 more answers
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