If an object on a spring became four times as massive, how would that affect the period of its oscillation on the spring?

2 answers:

6 0

The formula for the time period oscillation of a spring is:
T = 2π√(m/k) where m is the mass of the object attached to the spring and k is the spring constant of the spring.

Multiplying m by 4 we have:
2π√(4m/k)
= 2π x 2√(m/k)
or 2 x (2π√(m/k)) or 2T.

Therefore, when object is four times as massive, then period will double.

Daniel [21]3 years ago

4 0

Yup it'll double.. doing this on plato

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