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3 years ago

If you push an elephant and mouse with the same force, which would accelerate the least, why?

Physics

2 answers:

OverLord2011 [107]3 years ago

8 0

Answer: The Elephant

Explanation: Well i really don't know but i'ma going to take a guess

The Elephant is bigger and will be harder to push the the mouse. Sorry and have a great day :)

Nataly_w [17]3 years ago

4 0

Ofcoure the elephante as the elephant has more weight

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For the question below which equation should be used?

velikii [3]

Answer:

Equation 2

Explanation:

Initial velocity ( Vo ) = 20 m/s

Acceleration ( a ) = 1.1 m/s^2

Distance ( d ) = 55 m

Final velocity ( Vi ) can be found using equation 2

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2 years ago

If you measure the mass of a model car to be 230 grams, but the actual mass is 218 grams, what is your percent error?

konstantin123 [22]

Mass of a model car you measured = 230 grams

Actual mass = 218 grams

Percent error = ?

First subtract the actual value from the value you measured,

230 grams – 218 grams = 12 grams

Now divide 12 grams by the actual mass that is 218 grams:

12 / 218 = 0.055

Now multiply 0.055 with 100 to get the percent error;

0.055 x 100 = 5.5%

So, the Percent error is 5.5%.

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4 years ago

A 6.9-kg wheel with geometric radius m has radius of gyration computed about its mass center given by m. A massless bar at angle

Vilka [71]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is $\alpha =2.538 \ rad/s^2$

Explanation:

From the question we are told that

The mass of the wheel is m = 6.9 kg

The radius is $r = 0.69 \ m$

The radius of gyration is $k_G = 0.4\ m$

The angle is $\theta = 47^o$

The force which the massless bar is subjected to $F = 22.5 \ N$

Generally given that the wheels rolls without slipping on the flat stationary ground surface, it implies that point A is the center of rotation.

Generally the moment of inertia about A is mathematically represented as

$I_a = I_G + M* r^2$

Here $I_G$ is the moment of inertia about G with respect to the radius of gyration which is mathematically represented as

$I_G = M * k_G$

=> $I_a = k_G* M + M* r^2$

=> $I_a =0.4 * 6.9 + 6.9 * 0.69^2$

=> $I_a =6.045 \ kg \cdot m^2$

Generally the torque experienced by the wheel is mathematically represented as

$\tau = F * cos (47)$

=> $\tau = 22.5 * cos (47)$

=> $\tau = 15.34 \ kg \cdot m^2 \cdot s^{-2}$

Generally this torque is also mathematically represented as

$\tau = I_a * \alpha$

=> $15.34 = 6.045 * \alpha$

=> $\alpha =2.538 \ rad/s^2$

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3 years ago

What distance in cm does the light travel in 1 us?

Maksim231197 [3]

108000000. there you go hope it helped

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3 years ago

What is hydraulic pressure

Gnesinka [82]

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3 years ago