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shusha [124]
3 years ago
13

10 solve the following humeric problem - S. a What is the lift height of salu? T. object energy required to 25 kg to mass of a 1

0 m.
​
Physics
1 answer:
Salsk061 [2.6K]3 years ago
6 0
  • Mass=m=25kg
  • Height=h=10m
  • Acceleration due to gravity=g=10m/s^2

\boxed{\sf E_P=mgh}

\\ \sf\longmapsto E_P=25(10)(10)

\\ \sf\longmapsto E_P=25(100)

\\ \sf\longmapsto E_P=2500J

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Find the average force exerted by the bat on the ball if the two are in contact for 0.00129 s. Answer in units of N.
Semmy [17]

Answer:

Explanation:

Given

time of contact between bat and ball is t=0.00129 s

suppose u is the incoming velocity and v is the final velocity after collision

m=mass\ of\ ball

Impulse exerted is given by change in momentum of the particle.

Initial momentum P_i=m\times u

Final momentum P_f=m\times v

Change in momentum \Delta P=P_i-P_f

Impulse    J=F_{avg}\cdot t=\Delta P

J=F_{avg}\cdot t=m(u-v)

F_{avg}=\frac{m(v-u)}{t}

F_{avg}=775.2\times m(v-u)\ N                

5 0
3 years ago
You are comparing two diffraction gratings using two different lasers: a green laser and a red laser. You do these two experimen
Nikolay [14]

Answer:

a. (a) grating A has more lines/mm; (b) the first maximum less than 1 meter away from the center

Explanation:

Let  n₁ and n₂ be no of lines per unit length  of grating A and B respectively.

λ₁ and λ₂ be wave lengths of green and red respectively , D be distance of screen and d₁ and d₂ be distance between two slits of grating A and B ,

Distance of first maxima for green light

= λ₁ D/ d₁

Distance of first maxima for red light

= λ₂ D/ d₂

Given that

λ₁ D/ d₁ = λ₂ D/ d₂

λ₁ / d₁ = λ₂ / d₂

λ₁ / λ₂  = d₁ / d₂

But

λ₁  <  λ₂

d₁ < d₂

Therefore no of lines per unit length of grating A will be more because

no of lines per unit length  ∝ 1 / d

If grating B is illuminated with green light first maxima will be at distance

λ₁ D/ d₂

As λ₁ < λ₂

λ₁ D/ d₂ < λ₂ D/ d₂

λ₁ D/ d₂ < 1 m

In this case position of first maxima will be less than 1 meter.

Option a is correct .

5 0
3 years ago
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Alenkinab [10]

Which best describes the transition from gas to liquid?

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8 0
3 years ago
Read 2 more answers
If an experiment used 945 j of heat, how many calories (cal) is that?
irina1246 [14]
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A: 225.75
5 0
3 years ago
At any angular speed, a certain uniform solid sphere of diameter D has half as much rotational kinetic energy as a certain unifo
Trava [24]

Answer:

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let the angular velocity =  \omega

the radius of sphere (r) = \frac{D}{2}

moment of inertia of solid sphere I_s = 2/5 M(\frac{D}{2})^2

rotational K.E of solid sphere= \frac{1}{2}* I_s* \omega ^2

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we represent the mass of hallow sphere= M_{hs}

moment of inertia of solid sphereI_{ss} = 2/3 M_{hs}(\frac{D}{2})^2

rotational K.E of hollow sphere= \frac{1}{2}* I_{ss} * \omega^2

= 1/2 *2/3 M_{hs}(\frac{D}{2})^2* \omega^2

NOW,the kinetic energy of solid sphere= 1/2 kinetic energy of hallow sphere

=1/2 [2/5 M(D/2)^2 ]\omega^2= 1/2 (1/2 (2/3 M_{hs}(D/2)^2 )\omega^2 }

2/5M= 1/3 M_{hs}

M_{hs} = 3(2/5M)

M_{hs} = 6/5 M

7 0
3 years ago
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