Answer:
Explanation:
Given
time of contact between bat and ball is 
suppose u is the incoming velocity and v is the final velocity after collision

Impulse exerted is given by change in momentum of the particle.
Initial momentum 
Final momentum 
Change in momentum 
Impulse 


Answer:
a. (a) grating A has more lines/mm; (b) the first maximum less than 1 meter away from the center
Explanation:
Let n₁ and n₂ be no of lines per unit length of grating A and B respectively.
λ₁ and λ₂ be wave lengths of green and red respectively , D be distance of screen and d₁ and d₂ be distance between two slits of grating A and B ,
Distance of first maxima for green light
= λ₁ D/ d₁
Distance of first maxima for red light
= λ₂ D/ d₂
Given that
λ₁ D/ d₁ = λ₂ D/ d₂
λ₁ / d₁ = λ₂ / d₂
λ₁ / λ₂ = d₁ / d₂
But
λ₁ < λ₂
d₁ < d₂
Therefore no of lines per unit length of grating A will be more because
no of lines per unit length ∝ 1 / d
If grating B is illuminated with green light first maxima will be at distance
λ₁ D/ d₂
As λ₁ < λ₂
λ₁ D/ d₂ < λ₂ D/ d₂
λ₁ D/ d₂ < 1 m
In this case position of first maxima will be less than 1 meter.
Option a is correct .
Which best describes the transition from gas to liquid?
gas is @ higher energy state than liq. so the transition must remove energy. so ans is a. Energy must be removed because particles in liquid move more slowly.
There are approximately two hundred and twenty-five point seven five calories from using 945 j of heat
A: 225.75
Answer:
d. 6/5 M.
Explanation:
let the angular velocity = 
the radius of sphere (r) = 
moment of inertia of solid sphere
= 
rotational K.E of solid sphere= 
= 
we represent the mass of hallow sphere= 
moment of inertia of solid sphere
= 
rotational K.E of hollow sphere= 
= 
NOW,the kinetic energy of solid sphere= 1/2 kinetic energy of hallow sphere
=![1/2 [2/5 M(D/2)^2 ]\omega^2= 1/2 (1/2 (2/3 M_{hs}(D/2)^2 )\omega^2 }](https://tex.z-dn.net/?f=1%2F2%20%5B2%2F5%20M%28D%2F2%29%5E2%20%5D%5Comega%5E2%3D%201%2F2%20%281%2F2%20%282%2F3%20M_%7Bhs%7D%28D%2F2%29%5E2%20%29%5Comega%5E2%20%7D)
2/5M= 1/3
= 3(2/5M)
= 6/5 M