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elixir [45]
2 years ago
14

Which type of chemical reaction needs to absorb energy to proceed

Physics
1 answer:
natta225 [31]2 years ago
5 0
An endothermic reaction 
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A dog sits 2.6 m from the center of a merry- go-round. a) If the dog undergoes a 1.7 m/s^2 centripetal acceleration, what is the
alexgriva [62]

Answer:

a) v= 2.1 m/s

b) ω = 0.807 rad/s

Explanation

Conceptual analysis :

The dog and the merry-go- round describes a circular motion, then, the following formulas apply :

a_{c} =\frac{v^{2} }{r} Formula (1)

v = ω *r   Formula (2)

Where:

a_{c} : Centripetal acceleration(m/s²)

v: linear speed or tangential (m/s)

r :  radius of the circle (m)

ω : angular speed ( rad/s)

Data

r= 2.6 m

a_{c} =  1.7 m/s²

Problem develpment

a) We replace data in the formula 1 to calculate the dog's linear speed(v):

a_{c} =\frac{v^{2} }{r}

1.7 =\frac{v^{2} }{2.6}

v^{2} =1.7*2.6 = 4.42

v=(\sqrt{4.42})\frac{m}{s}

v= 2.1 m/s

b)We replace data in the formula 2 to calculate the angular speed of the merry-go- round (ω).

v = ω *r

2.1 = ω *2.6

ω = 2.1/2.6

ω = 0.807 rad/s

6 0
3 years ago
PLZ HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!<br> What is a front?
Shkiper50 [21]

Answer:

in computer and writing context it is many styles of writing that you can make the text look like. I.E: <em>helllo  </em>hello

Explanation:

A font is the combination of typeface and other qualities, such as size, pitch, and spacing. For example, Times Roman is a typeface that defines the shape of each character. Within Times Roman, however, there are many fonts to choose from -- different sizes, italic, bold, and so on.

Mark me the brainliest plz

4 0
2 years ago
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What name is given to the wall of water that makes landfall just ahead of a hurricane?
andreev551 [17]
Pretty sure its a. storm surge 
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3 years ago
A solid cylinder is released from the top of an inclined plane of height 0.81 m. From what height, in meters, on the incline sho
Jlenok [28]

Answer:

same 0.81m

Explanation:

in this problem if we assume there no resistance of any sort. and we apply the energy conservation

change in Potential energy = change in kinetic energy

mgh = 0.5mv^2

gh = 0.5v^2

the above relation suggests that the speed at the bottom is only depending on the height it is released from not on the shape, mass or radius.

so at the bottom

put h = 0.81m

9.81 * 0.81 * 2 = v^2

v=3.99 m/s

both CYLINDER and SPHERE will have same velocity at the bottom if released from the same height irrespective of shape and size

3 0
3 years ago
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Greeley [361]
I think it’s 8 hours. I’m sorry if I’m wrong.
I just did 400 divided by 50
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