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hammer [34]
3 years ago
13

Help me please! Thank u

Mathematics
1 answer:
Ahat [919]3 years ago
6 0

Answer:

D is correct answer to the question

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Find the perimeter of the shaded region. Round your answer to the nearest hundredth.
nataly862011 [7]

Answer:

59.16  units

Step-by-step explanation:

Given that,

The length of rectangle, L = 13

The breadth of the rectangle, B = 6

The perimeter of the shaded region = perimeter of rectangle - 2(perimeter of semicircle)

P=13\times 6-[2\times \dfrac{2\pi r}{2}]\\\\=78-2\pi r\\\\=78-2\times 3.14\times 3\\\\=59.16

So, the perimeter of the shaded region is 59.16  units.

4 0
3 years ago
During the summer, the height of the water in the pool decreased by 5 inches each week due to evaporation. What is the change in
rjkz [21]

Answer:

40 inches

Step-by-step explanation:

We know that the height of water in a pool decreased 5 inches per week.

This means that we can form the equation y=-5x, since the amount of water remaining is proportionate to the amount of weeks that have passed.

We know x=8, since we need to find the change for 8 weeks.

y = -5\cdot 8

-5 \cdot 8 = -40

y=-40

The change will be the absolute value of -40, which just makes it positive, so 40.

Hope this helped!

8 0
3 years ago
Read 2 more answers
SAME SCENARIO - DIFFERENT QUESTION
Dvinal [7]

Answer:

20=XY

Step-by-step explanation:

7 0
2 years ago
There are 25 students who answered a survey about sports. Four-fiths of them like football. How many students like football?
exis [7]

Answer:

20

Step-by-step explanation:

25/5 = 5

5 x 4 = 20

6 0
3 years ago
Read 2 more answers
{ TOPIC -- TRIGONOMETRIC IDENTITIES }
UkoKoshka [18]
LHS ⇒ RHS:
Identities:
[1] cos(2A) = 2cos²(A) - 1 = 1 - 2sin²(A)
[2] sin(2A) = 2sin(A)cos(A)
[3] sin(A + B) = sin(A)cos(B) + cos(A)sin(B)
[4] cos(A + B) = cos(A)cos(B) - sin(A)sin(B)

cos(x) - cos(x + 2Θ)
= cos(x) - (cos(x)cos(2Θ) - sin(x)sin(2Θ))    [4]
= cos(x) - cos(x)(1 - 2sin²(Θ)) + sin(x)(2sin(Θ)cos(Θ))    [1] [2]
= cos(x) - cos(x) + 2sin²(Θ)cos(x) + 2sin(Θ)sin(x)cos(Θ)
= 2sin²(Θ)cos(x) + 2sin(Θ)sin(x)cos(Θ)
= 2sin(Θ)(sin(Θ)cos(x) + sin(x)cos(Θ))
= 2sin(Θ)sin(x + Θ)
8 0
2 years ago
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