Answer:
The kite is 109.7 ft off the ground.
Step-by-step explanation:
Raul is flying a kite at the end of a string that is 250 feet long.
Raul is holding the string 4 feet off the ground at the angle to the horizontal as shown in the attached diagram.
We want to find out how high is the kite off the ground.
Recall from the trigonometric Identities,
Here we are given the hypotenuse that is 250 ft and opposite is the unknown height
We know that Raul is holding the string 4 feet off the ground so
105.7 + 4 = 109.7 ft
Therefore, the kite is 109.7 ft off the ground.
Answer:
14
Step-by-step explanation:
All of the angles are marked as congruent, which means it is an equlateral triangle. This means that all of the sides are congruent too.
Therefore z + 2 = 2z -10
add 10 to each side
z + 12 = 2z
subtract z from each side
12=z
now that we know that, we can plug it back in to either line (it doesn't matter because they're congruent)
line AB is z+2 which is 12+2 or 14
and line CB is 2z-10 which is 2(12)-10 or 24-10 which is also 14
so line CA is also 14 units long.
Answer:
A
Step-by-step explanation:
oh steps are here!
Answer:
£707.8
Step-by-step explanation:
Given data
Price= £800
Rate= 4%
Time= 3 years
Let us apply the compounding formula
A=P(1-r)^r-------------Note the negative sign is because of depreciation
substitute
A= 800(1-0.04)^3
A= 800(0.96)^3
A=800*0.884736
A= £707.8
Hence the value will be £707.8
Answer:
(a)
(b)5,832 Mosquitoes
(c)5 days
Step-by-step explanation:
(a)Given an original amount at t=0. The population of the colony with a growth rate , where k is a constant is given as:
(b)If and the population after 1 day, N(1)=1800
Then, from our model:
N(1)=1800
Therefore, our model is:
In 3 days time
The population of mosquitoes in 3 days time will be approximately 5832.
(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.
From our model
In approximately 5 days, the population of mosquitoes will be 20,000.