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3 years ago

Unit 2

Mathematics

1 answer:

34kurt3 years ago

6 0

Answer:

A 21 mm

Step-by-step explanation:

u have to divided and then subtract

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-4+2(12)<br> ————<br> -3(-3)-(-1)

dsp73

Answer:

20/10 is 2

final answer is 2

8 0

3 years ago

What's the numerator for the following rational<br> expression?<br> X/y + 3/y= ?/y

Fittoniya [83]

Answer:

x + 3

Step-by-step explanation:

Since we have a common denominator, we can just simply combine the numerator which is just x+3.

7 0

3 years ago

Three solutions for the linear equation 4 −3 = 1.

FrozenT [24]

Answer:

(1, 1), (2, 2.333) and (3, 3.666).

Step-by-step explanation:

So, for x = 1, we have:

4*1 - 3y = 1

3y = 3

y = 1

For x = 2, we have:

4*2 - 3y = 1

3y = 7

y = 2.333

For x = 3, we have:

4*3 - 3y = 1

3y = 11

y = 3.666

The points we need to plot is (1, 1), (2, 2.333) and (3, 3.666).

4 0

3 years ago

How do you write 18/40 in a decimal

In-s [12.5K]

Answer:

0.45 you divide them

4 0

3 years ago

Read 2 more answers

natima [27]

Answer:

See explanation

Step-by-step explanation:

Let x be the number of spade shovels, y -the number of flat shovels and z - the number of square showels sold that day.

The store keeps an inventory of 80 shovels, then

x+y+z=80

The store always buy twice as many spade shovels as square, so

x=2z

The total cost of all shovels is

16x+9.60y+12.80z=1,072

a) The system of three equations is

$\left\{\begin{array}{l}x+y+z=80\\ \\x=2z\\ \\16x+9.60y+12.80z=1,072\end{array}\right.$

b) In matrix form this is

$\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}80\\0\\1,072\end{array}\right)$

c) The determinant is

$\left\|\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right\|=0-32+9.60-0+19.20-12.80=-16$

d) Find three determinants:

$\left\|\begin{array}{ccc}80&1&1\\ 0&0&-2\\ 1,072&9.60&12.80\end{array}\right\|=0-2,144+0-0+1,536-0=-608$

$\left\|\begin{array}{ccc}1&80&1\\ 1&0&-2\\ 16&1,072&12.80\end{array}\right\|=0-2,560+1,072-0+2,144-1,024=-368$

$\left\|\begin{array}{ccc}1&1&80\\ 1&0&0\\ 16&9.60&1,072\end{array}\right\|=0+0+768-0-0-1,072=-304$

So,

$x=\dfrac{-608}{-16}=38\\ \\y=\dfrac{-368}{-16}=23\\ \\z=\dfrac{-304}{-16}=19$

e) If the store doubled all prices and inventory, then the new matrix is

$\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 32&19.20&25.60\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}160\\0\\2,144\end{array}\right)$

7 0

3 years ago