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taurus [48]
3 years ago
10

True or false: Mass is conserved in physical but not chemical changes in matter. idc

Chemistry
2 answers:
lisabon 2012 [21]3 years ago
7 0

Answer:

False matter in conserved in both forms according to the law of conservation of mass.

Explanation:

lions [1.4K]3 years ago
5 0

Answer: well im not sure 100% but ima go with false because matter is the one that doesent change

Explanation: hope it helps :)

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The total volume of a soda can is 415 mL. Of this 415 mL, there is 60.0 mL of headspace(empty space aka volume) for the CO2 gas
almond37 [142]

Answer:

gay

Explanation:

6 0
2 years ago
If you lived in Flagstaff, Arizona, how much salt (NaCl) would you have to add to your spaghetti water to get it to boil at 100
nasty-shy [4]

Answer:

Explanation:

This question is both theoretical and practical. While the theoretical aspect will be detailed fully here, the practical aspect will be provided as a form of guidance.

Water generally boils at 100°C when altitude (in feet) is 0. One of the colligative properties that occurs <u>when salt is added to water is that there is a boiling point elevation</u>(meaning an increase in boiling point). For instance, if 20g of salt is added to about 5.3 quarts of water, the boiling point of water will increase from 100°C to 100.04°C.

However, when the altitude/elevation of a place is about 7000 ft (like in Flagstaff, Arizona), water will boil at 95.3°C. In order to get 2 quarts of water to boil at 100°C in Flagstaff;

20g causes an increase in boiling point by 0.04°C (100°C to 100.04°C) in 5.3 quarts of water

What gram will increase the boiling point by same 0.04°C in 2 quarts

20g ⇒ 5.3

X ⇒ 2

5.3 X ⇒ 40g

X = 40 ÷ 5.3

X = 7.55g

Hence, 7.55g will cause an increase in boiling point by 0.04°C (from 100°C to 100.04°C) in 2 quarts of water

What mass of salt will increase the boiling point by 4.7°C (95.3°C to 100°C)

7.55g ⇒ 0.04

X ⇒ 4.7

X × 0.04 ⇒ 7.55 × 4.7

0.04X ⇒ 35.5

X = 887.5g

Hence, in order for the spaghetti water to boil at 100°C, 887.5g of salt needs to be added.

For the practical part of the question, some Kitchen scales have an accuracy of .25kg (250g) and some have an accuracy of .2 kg (200g) and some have an accuracy of .5kg (500g). The one your kitchen has will determine the amount of salt that you can measure. For example, if your kitchen scale/balance has an accuracy of 250g/0.25kg, then you can only measure 750g of the 887.5g (as the rest is 137.5g, which is not up to 250g of the scale's accuracy) of the required salt measurement. However, if you have a digital balance that can measure up to 2kg/2000g in one decimal place, that's the perfect balance to measure this salt.

5 0
3 years ago
A solution containing HCl and the weak acid HClO2 has a pH of 2.4. Enough KOH (aq) is added to the solution to increase the pH t
astraxan [27]

Answer:

\boxed{\rm \text{[ClO$_{2}^{-}$] increases}}

Explanation:

At the beginning, you have two reactions happening:

\rm HCl + H$_{2}$O$ $\, \longrightarrow \,$ H$_{3}$O$^{+}$ + Cl$^{-}$\\\rm HClO$_{2}$ + H$_{2}$O$ $\, \rightleftharpoons \,$ H$_{3}$O$^{+}$ + ClO$_{2}^{-}$

As you add KOH(aq), it does two things:

  1. It increases the volume of the solution.
  2. It reacts with the hydronium ions to form water.

A) The HCl is completely ionized. The Cl⁻ does not react, but it is diluted when the volume of the solution increases. [Cl⁻] decreases.

B) The KOH reacts with the H⁺ and removes it from the solution. [H⁺] decreases.

C) When all the H⁺ from the HCl has been neutralized, the KOH starts neutralizing the H⁺ from the HClO₂. According to Le Châtelier's Principle, more HClO₂ will dissociate to replace the decreased H⁺. [HClO₂] decreases.

D) As HClO₂ reacts, it forms ClO₂⁻. \boxed{\rm \textbf{[ClO$_{2}^{-}$] increases}}

7 0
3 years ago
Do Halogens gain or lose electrons to form ions
Llana [10]
Halogens are among the most reactive of all elements. They have seven valence electrons, so they are very “eager” to gain one electron to have a full outer energy level. So they gain
4 0
3 years ago
What is the pressure of 0.33 moles of nitrogen gas, if its volume is 15.0 L at –25.0oC?
musickatia [10]

Using the ideal gas law PV =nRTPV=nRT , we find that the pressure will be P =\frac{nRT}{V}P=

V

nRT

​

 . Then, we'll substitute and find the pressure, using T = -25 °C = 248.15 K and R = 0.0821 \frac{atm\cdot L}{mol \cdot K}

mol⋅K

atm⋅L

​

 :

P =\frac{nRT}{V} = \frac{(0.33\,\cancel{mol})(0.0821\frac{atm\cdot \cancel{L}}{\cancel{mol \cdot K}})(248.15\,\cancel{K})}{15.0\,\cancel{L}} = 0.4482\,atmP=

V

nRT

​

=

15.0

L

​

(0.33

mol

)(0.0821

mol⋅K

atm⋅

L

​

​

)(248.15

K

​

)

​

=0.4482atm

In conclusion, the pressure of this gas is P=0.4482 atm.

Reference:

Chang, R. (2010). Chemistry. McGraw-Hill, New York.

3 0
2 years ago
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