Answer:
When the following redox equation is balanced with smallest whole number coefficients, the coefficient for the iodide ion will be __6__.
Explanation:
From the redox equation, we can see that NO₃⁻ is reduced to NO (from oxidation state +5 to +2), whereas I⁻ is oxidized to I₂ (from oxidation state -1 to 0). The half reactions are balanced with H⁺ (acidic solution), as follows:
Reduction : 2 x (NO₃⁻(aq) + 3 e- + 4 H⁺ → NO(g) + 2 H₂O)
Oxidation : 3 x (2 I⁻(aq) → I₂(s) + 2 e-)
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Total equation: 6 I⁻(aq) + 2 NO₃⁻(aq)+ 8 H⁺ → 3 I₂(s) + 2 NO(g) + 4 H₂O
That is the redox equation with the smallest whole number coefficients.
Accordin to this, the coefficient for the iodide ion (I⁻) is: 6.
Answer:
6moles of O2 will be produced
Explanation:
Step 1: write the correct and balance the equation
2KClO3 --------> 2KCl + 3O2
Step 2: find the mole
2 moles of KClO3 gives 3moles of O2
We are provided with 4 moles of KClO3,
Since 2 moles of KClO3 = 3 moles of O2
4 moles of KClO3 = x moles of O2
Cross multiply
2 = 3
4 = x
4 * 3 = 2 * x
12 = 2x
Divide both sides by 2 , to get the mole of O2
12/2 = 2x/ 2
6 = x
x = 6
The mole of O2 is 6 moles
They do not move they stay in the same same place it may look like they move because of the earth rotation
Answer:
C₈H₁₈ + 25/2O₂ —> 8CO₂ + 9H₂O
2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O
Explanation:
The reaction above is simply termed combustion reaction in which an organic compound react with oxygen to produce carbon dioxide and water. Thus, we can obtain the balanced equation for the reaction reaction as follow:
C₈H₁₈ + O₂ —> CO₂ + H₂O
There are 8 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 8 before CO₂ as shown below:
C₈H₁₈ + O₂ —> 8CO₂ + H₂O
There are 18 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 9 before H₂O as shown below:
C₈H₁₈ + O₂ —> 8CO₂ + 9H₂O
There are 2 atoms of O on the left side and a total of 25 atoms on the right side. It can be balance by writing 25/2 before O₂ as shown below:
C₈H₁₈ + 25/2O₂ —> 8CO₂ + 9H₂O
Thus, the equation is balanced!
The above equation can also be written as follow:
C₈H₁₈ + 25/2O₂ —> 8CO₂ + 9H₂O
Multiply through by 2
2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O