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Semmy [17]
2 years ago
14

In the triangle above, the measure of R is 59°.

Mathematics
2 answers:
stiv31 [10]2 years ago
5 0
I say d I believe I’m right
White raven [17]2 years ago
3 0
I say d maybe tell me if I’m right
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Kathleen wants to plant a small vegetable garden in her yard. She fences off a rectangular area with a length of 25.75 feet and
Fofino [41]

Answer:

A= L x W

A= 25.75 X 10.2

A= 262.65

Step-by-step explanation:

THE AREA OF KATHLEEN'S VEGETABLE GARDEN

5 0
2 years ago
46 POINTS!!!!!!!!!!!!!<br><br> Simplify the expression 23r - 23r<br><br> please help me UwU
Lorico [155]

Answer:

1r-1r

Step-by-step explanation:

srry if its wrong i took that class a couple months ago

7 0
3 years ago
4(x)+6+3=17 what does x equal
gogolik [260]

Hello There!

X=2

To solve this, we first need to understand that when we see an X in parentheses, we multiply the number before it in this case 4 by X.

The answer is 2 because we multiply 4 by 2 which is the x value so 4*2 is equal to 8 and they we add 9 to it because the sum of 6 and 3 is 9.

Finally, our answer we get is 17 so our X value is 2.

Have A Great Day!

4 0
3 years ago
How many degrees are in the angle formed by the hands of the clock?
QveST [7]

Answer:

90°

Step-by-step explanation:

15 mins = 1/4 of full circle

1/4 of 360 = 90

90°

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

6 0
2 years ago
Read 2 more answers
The clutch linkage on a vehicle has an overall advantage of 24:1. If the pressure plate applies a force of 504lb,how much force
Anon25 [30]

Answer:

the force that must be applied by the driver to release the clutch is 21 lb

Step-by-step explanation:

Data provided:

clutch linkage on a vehicle has an overall advantage = 24:1

Applied force by the pressure plate = 504 lb

Now,

the advantage ratio is given as:

advantage ratio = \frac{\textup{Force applied by the pressure plate}}{\textup{Force applied by the driver}}

on substituting the respective values, we get

\frac{\textup{24}}{\textup{1}}  = \frac{\textup{504 lb}}{\textup{Force applied by the driver}}

or

Force applied by the driver to release the clutch = \frac{\textup{504 lb}}{\textup24}}

or

Force applied by the driver to release the clutch = 21 lb

Hence,

the force that must be applied by the driver to release the clutch is 21 lb

6 0
3 years ago
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