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madam [21]
3 years ago
14

Sulfur is an element that can be seen on the periodic table. What will most likely occur if sulfur forms an ionic bond with anot

her element?
Sulfur will accept electrons.
Sulfur will donate electrons.
Sulfur will become a positive ion.
Sulfur will become less stable.
Chemistry
2 answers:
Yakvenalex [24]3 years ago
8 0

What is likely  to occur  if sulfur  forms an ionic  bond with another  element  is  <u>sulfur  will accept  electrons</u>

     

    <u><em> explanation</em></u>

  • Ionic bond is formed when  a metal react with a non metal.
  • Metal  loses ( donate) electrons  to form cation ( a positively charged  ion) , while  non metal accept (gain)  electrons  to form anion ( a negatively charged ion ).

  • Sulfur  is a non metal  therefore it  accept  electrons if it form an ionic bond  with a metal. sulfur accept  2 electrons to  form S2- ion

Norma-Jean [14]3 years ago
3 0
Sulfur will accept electrons.
Sulfur want's to be perfect but it lacks Electrons so when it makes an Ionic bond it will take the Electrons instead of giving them away
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Can someone help me thank you. I have to look at each picture and determine if the circuits shown are series circuits or paralle
rodikova [14]

Answer:

I believe it may be-

1. Series

2. Parallel

3. Parallel

4. Series

Explanation:

In a series circuit, electricity only has one path to follow while a parallel circuit has more than one path to follow.

7 0
2 years ago
The temperature in a town started out at 55 degrees. By the end of the day the temperature dropped to -6 degrees.
garik1379 [7]

Answer:

The choice of the answer is fourth option that is -61 degrees.

Therefore the temperature drop is -61°Centigrade.

Explanation:

Given:

The temperature in a town started out at 55 degrees

Start temperature = 55°Centigrade. (Initial temperature)

End of the Day      = -6°Centigrade. (Final temperature)

To Find:

How far did the temperature drop?

Solution:

We will have,

\textrm{Temperature drop}=\textrm{Final temperature}-\textrm{Initial temperature}

Substituting the above values in it we get

\textrm{Temperature drop}=-6-55\\\\\therefore \textrm{Temperature drop}=-61\° centigrade

Therefore the temperature drop is -61°Centigrade.

4 0
3 years ago
A tank at is filled with of chlorine pentafluoride gas and of sulfur hexafluoride gas. You can assume both gases behave as ideal
Ivan

Answer:

- Mole fraction of Chlorine Pentafluoride

= 0.265

- Partial Pressure of Chlorine Pentafluoride

= 16.05 kPa

- Mole fraction of Sulfur Hexafluoride

= 0.735

- Partial Pressure of Sulfur Hexafluoride

= 44.53 kPa

Total Pressure exerted by the gases = 60.58 kPa

Explanation:

First of, we calculate the number of moles of each gas present.

Number of moles = (Mass)/(Molar Mass)

For ClF₅

Mass = 4.28 g

Molar Mass = 130.445 g/mol

number of moles of Chlorine Pentafluoride

= (4.28/130.445) = 0.0328 moles

For SF₆

Mass = 13.3 g

Molar Mass = 146.06 g/mol

number of moles of Sulfur Hexafluoride

= (13.3/146.06) = 0.0911 moles

Total number of moles present = 0.0328 + 0.0911 = 0.1239 moles.

Using the ideal gas equation

PV = nRT

P = total pressure in the tank = ?

V = volume of the tank = 5.00 L = 0.005 m³

R = molar gas constant = 8.314 J/mol.K

T = temperature of the tank = 20.9°C = 294.05 K

n = total number of moles present = 0.1239 moles

P × 0.005 = (0.1239 × 8.314 × 294.05)

P = 60,580.45 Pa = 60.58 kPa.

- Mole fraction of a particular component of interest = (number of moles of the component of interest) ÷ (total number of moles)

- Partial Pressure of a particular component of interest = (mole fraction of that component of interest) × (total pressure)

This is Dalton's law of Partial Pressure.

- Mole fraction of Chlorine Pentafluoride

= (0.0328/0.1239) = 0.265

- Partial Pressure of Chlorine Pentafluoride

= 0.265 × 60.58 = 16.05 kPa

- Mole fraction of Sulfur Hexafluoride

= (0.0911/0.1239) = 0.735

- Partial Pressure of Sulfur Hexafluoride

= 0.735 × 60.58 = 44.53 kPa

Total Pressure exerted by the gases = 16.04 + 44.53 = 60.58 kPa

Hope this Helps!!!

3 0
3 years ago
In an experiment, 4.14 g of phosphorus combined with chlorine to produce 27.8 g of a white solid compound. what is the empirical
Umnica [9.8K]

Grams of Phosphorus = 4.14 grams 
Grams of white compound = 27.8 grams 
Grams of Chlorine would be = 27.8 - 4.14 = 23.66 grams
 Calculating moles which would be grams / molar mass
 Molar mass of P = 30.97 grams / moles; Molar mass of Cl = 35.45 grams / moles
 Moles of Phosphorus = 4.14 grams / 30.97 grams / moles = 0.1337 moles
 Moles of Chlorine = 23.66 grams / 35.45 grams / moles = 0.6674 moles
 Calculating the ratios by dividing with the small entity
 P = 0.1337 moles / 0.1337 moles = 1
 Cl = 0.6674 moles / 0.1337 moles = 5 
So the empirical formula would be PCl5
3 0
3 years ago
What type of reaction is this?—- Large Compound=Element A+Element B
Sav [38]
This reaction is decomposition. It is the breakdown of a compound into simpler and smaller elements.
6 0
2 years ago
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