Answer:
Explanation:
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In this case, according to the given combustion reaction of octane, it is possible for us to perform the stoichiometric method in order to calculate the mass of octane that is required to consume 300.0 g of oxygen by considering the 2:25 mole ratio, and the molar masses of 114.22 g/mol and 32.00 g/mol respectively:
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Answer:
The density of ozone is 4.24.
Explanation:
The relation between the relative rate of diffusion and density is given by :
The given ratio of the relative rate of diffusion of ozone as compared to chlorine is 6:3.
Let the density of ozone is d₂.
So, the density of ozone is 4.24.
The awnser is D or the 4th one
Answer: v2=331.289mL
Explanation:
Formula for ideal gas law is p1v1/T1=p2v2/T2
P1=782.3mmHg
P2=769mmHg at STP
V1=362.4mL
V2=?
T1=273+34.4=307.4k
T2=273k at STP
Then apply the formula and make v2 the subject of formula
V2= 782.3×362.4×273/760×307.4
V2=77397006.96/233624
V2=331.289mL
Atomic number is equal to protons and electrons, so the answer is 5
