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romanna [79]
3 years ago
14

What amount of heat will raise the temperature of 78g liquid water from 20 C to 80 C?

Chemistry
1 answer:
DaniilM [7]3 years ago
3 0

Answer:

19656J

Explanation:

Step 1:

Data obtained from the question.

Mass (M) = 78g

Initial temperature (T1) = 20°C

Final temperature (T2) = 80°C

Change in temperature (ΔT) = T2 – T1 =

80°C – 20°C = 60°C

Specific heat capacity (C) = 4.2J/g°C

Heat (Q) =...?

Step 2:

Determination of the heat required for the reaction.

Q = MCΔT

Q = 78 x 4.2 x 60

Q = 19656J

Therefore, 19656J of heat is required.

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Answer:

a.the smallest building blocks of matter

Explanation:

because atoms are the smallest building blocks of matter.

3 0
3 years ago
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Do you think there should be greater restrictions on who can buy explosives or accelerants? Why or why not?
fgiga [73]
In my opinion yes, as of now, almost anyone could get there hands on lets say an explosive. Have you heard of dynamite fishing? It is illegal, but it is still done once people have access to dynamite, then what ends up happening not only do marine wildlife get killed but it pollutes the water and lessens the chance of the natural cycle of life. Also there are several other factors, firstly, what will you do with an explosive once you get your hands on it? Perhaps you could just use an explosive for fun/personal entertainment...that isn't right and it could harm people. So, to conclude the harder it is for people to access explosives or even acclerants the better...and to add this can be possible by making people get like some sort of licence to use them, and let them be trained in certain conditions so that there is no regrets once they have access to them. I know my idea sounds far fetched but its a thought!
4 0
3 years ago
How much heat is required to warm 1.50L of water from 25.0C to 100.0C? (Assume a density of 1.0g/mL for the water.)
Masteriza [31]

<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 1.50 L = 1500 mL    (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g

To calculate the heat absorbed by the water, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of water = 1500 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(100-25)^oC=75^oC

Putting values in above equation, we get:

q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ

Hence, the amount of heat required to warm given amount of water is 470.9 kJ

6 0
3 years ago
How many moles of potassium chloride are in 28 grams of KCl?
stiv31 [10]

Answer:

0.3758moles

Explanation:

moles of kcl = mass of kcl/ molar mass of kcl = 28/74.5 = 0.3758moles

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