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romanna [79]
3 years ago
14

What amount of heat will raise the temperature of 78g liquid water from 20 C to 80 C?

Chemistry
1 answer:
DaniilM [7]3 years ago
3 0

Answer:

19656J

Explanation:

Step 1:

Data obtained from the question.

Mass (M) = 78g

Initial temperature (T1) = 20°C

Final temperature (T2) = 80°C

Change in temperature (ΔT) = T2 – T1 =

80°C – 20°C = 60°C

Specific heat capacity (C) = 4.2J/g°C

Heat (Q) =...?

Step 2:

Determination of the heat required for the reaction.

Q = MCΔT

Q = 78 x 4.2 x 60

Q = 19656J

Therefore, 19656J of heat is required.

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Which of these solutions is the most basic?
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<h2>Question↷</h2>

Which of these solutions is the most basic?

[OH-] = 4.3 x 10-9 M

[OH-] = 2.8 x 10-11 M

[OH-] = 6.7 x 10-10 M

[OH-] = 1.0 x 10-5 M

<h2>Answer↷</h2>

  • <u>[OH-] = 1.0 x 10-5 M</u> ✓

<h2>Solution↷</h2>

[OH-] = 4.3 x 10-9 M

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  • pOH = - log [OH^1-]
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_______________________________________

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  • pOH = - log [OH^1-]
  • pOH = - log [2.8 x 10^-11 ]
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_______________________________________

[OH-] = 6.7 x 10-10 M

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  • pOH = - log [OH^1-]
  • pOH = - log [6.7 x 10^-10]
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  • pH = 14-9.17
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_______________________________________

[OH-] = 1.0 x 10-5 M

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  • pOH = - log [OH^1-]
  • pOH = - log [1.0 x 10^-5 ]
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  • pH = 9

_______________________________________

we know that , the solution with <u>pH > 7</u> is termed as basic and more the pH ,more the basicity, hence ,the solution with the highest pH would be the strongest base out of these all which is

<u>[OH-] = 1.0 x 10-5 M</u> with pH = 9

_______________________________________

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