K.E = 1/2 (mv^2)
K.E = 1/2(9.11*10^-31 kg)(2.50**10^6 m/s)^2
K.E = 2.85 X 10 ^-18 Joules
See the attachments too
120 acceleration oh yeah i am sure about this
Answer:
The Skater's final angular speed =8rad/s
Explanation:
Let initial momentum of inertia be I1
Let final momentum of inertia be I2
But I2= I1/2
It is decreased by one-half
There is no external torque on the system, therefore
I1w1=I2w2
I1×4=(I1/2)×w2
Dividing through by I1 on both sides leaves you with:
4=w2/2
Cross multiply
W2=4×2=8rad/s
0.030 hours
First part of run
d = 1.5 km
s = 85 km/h
t = d / s = 1.5/85
t1 = 0.017647 hours
Second part of run
d = 0.80 km
s = 67 km/h
t = d / s = 0.80/67
t2 = 0.011940 hours
t1 + t2 = 0.017647 + 0.011940
= 0.030 â„Žours
Complete Question:
Andy and Charlie are riding on a merry-go-round. Andy rides on a horse at the outer rim of the circular platform, twice as far from the center of the circular platform as Charlie, who rides on an inner horse. When the merry-go-round is rotating at a constant angular speed, which of the following best describes Andy's angular speed?'
( ) twice Charlie’s
( ) impossible to determine.
( ) the same as Charlie’s
( ) half of Charlie’s
Answer:
The same as Charlie's
Explanation:
As a merry-go-round is a rigid body, all points in the rotating body must have the same angular velocity, i.e., thet must rotate the same angle in the same time.
Otherwise, the distance between any pair of points on a given radius could be different in different times, which is not possible in a rigid body,