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Harrizon [31]
3 years ago
7

The n = 8 to n = 4 transition in the bohr hydrogen atom occurs in the __________ region of the electromagnetic spectrum.

Physics
2 answers:
tiny-mole [99]3 years ago
4 0
INFRARED REGION ..............
AleksandrR [38]3 years ago
3 0

<u>Answer</u>:

The n = 8 to n = 4 transition in the Bohr hydrogen atom occurs in the Infrared region of the electromagnetic spectrum.

<u>Explanation</u>:

The electron present in a hydrogen atom revolves around the nucleus in their orbits.The electron's energy in an orbit is proportional to its distance from the nucleus. Nearer the electron is from nucleus, the less energy it has. Only a limited number of orbits is allowed with certain energies.

When an electron jumps from an orbit of higher energy, it absorbs light and releases it when an electron falls into an orbit of lower energy. This transition from higher energy level to lower energy level takes place in different region .

When  electron in the hydrogen atom undergoes transition between n=4 energy level and n=8 energy levels it produces spectral line within the infrared region with wavelength of  4.05 to 1.46 microns. This is called as brackett series.

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The Earth itself is a source of terrestrial radiation. Radioactive materials including uranium, thorium, and radium exist naturally in soil and rock. Essentially all air contains radon<span> , which is responsible for most of the dose that Americans receive each year from natural background sources.</span>
4 0
3 years ago
Find the slit separation of a double-slit arrangement that will produce interference fringes 0.018 rad apart on a distant screen
inessss [21]

Answer:

1.64 * 10^(-5) m

Explanation:

Parameters given:

Angular separation, θ = 0.018 rad

Wavelength, λ = 589 nm = 5.89 * 10^(-7) m

The angular separation when there are 2 slots is given as

θ = λ/2d

where d = separation between slits

d = λ/2θ

d = (589 * 10^(-9))/(2 * 0.018)

d = 1.64 * 10^(-5) m

5 0
3 years ago
5b) how fast is the car going after 6 seconds?
jeka94

Answer:

No imageeeeeeeeeeeeeeeeeeeeee

8 0
3 years ago
Read 2 more answers
1. A car accelerates uniformly from 12 m/s to 39 m/s in 12 seconds. What is the car's average acceleration
Alinara [238K]

Answer:

(1) 2.25m/s^2

(2) 45.6m

Explanation:

(1) A car accelerates uniformly from 12m/s to 39m/s in 12 seconds

Therefore the average acceleration can be calculated as follows

a = 39-12/12

a = 27/12

a= 2.25m/s^2

(2) A butterfly is flying at 4m/s , it accelerates uniformly at 1.2 m/s for 6 seconds

u= 4

a= 1.2

t= 6

Therefore the distance can be calculated as follows

S= ut + 1/2at^2

= 4×6 + 1/2 × 1.2 × 6^2

= 24 + 1/2 × 1.2 × 36

= 24 + 1/2 × 43.2

= 24 + 21.6

S = 45.6m

Hence the butterfly travels at 45.6m

5 0
3 years ago
An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary
Alenkinab [10]

Answer:

T =  4200N

Explanation:

When the submersible craft is at rest, the tension in the cable is 6000N.

With this information you can calculate the weight of the craft by summing the forces (the summation of the force is zero because the craft is at rest):

T-W=0\\\\W=T=6000N

When the craft is going down with a constant speed, there is a drag force of 1800N. Then, by using the second Newton law you have:

T-W+F_d=0   (1)

Fd: drag force

The summation of the forces is zero because the craft moves with constant velocity, that is, there is no acceleration.

You calculate the new tension on the cable by solving the equation (1) for T:

T=W-Fd=6000N-1800N=4200N

hence, the tension is 4200N

5 0
3 years ago
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