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Harrizon [31]
3 years ago
7

The n = 8 to n = 4 transition in the bohr hydrogen atom occurs in the __________ region of the electromagnetic spectrum.

Physics
2 answers:
tiny-mole [99]3 years ago
4 0
INFRARED REGION ..............
AleksandrR [38]3 years ago
3 0

<u>Answer</u>:

The n = 8 to n = 4 transition in the Bohr hydrogen atom occurs in the Infrared region of the electromagnetic spectrum.

<u>Explanation</u>:

The electron present in a hydrogen atom revolves around the nucleus in their orbits.The electron's energy in an orbit is proportional to its distance from the nucleus. Nearer the electron is from nucleus, the less energy it has. Only a limited number of orbits is allowed with certain energies.

When an electron jumps from an orbit of higher energy, it absorbs light and releases it when an electron falls into an orbit of lower energy. This transition from higher energy level to lower energy level takes place in different region .

When  electron in the hydrogen atom undergoes transition between n=4 energy level and n=8 energy levels it produces spectral line within the infrared region with wavelength of  4.05 to 1.46 microns. This is called as brackett series.

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In an experiment to measure the acceleration due to gravity, g two values, 9.96 m/s2 and 9.72 m/s2 , are determined. Find (1) th
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(1) Percent Difference = 2.47%

(2) Percent Error (9.96 m/s²) = 1.63 %

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Explanation:

(1)

Percent Difference = [(9.96 m/s² - 9.72 m/s²)/(9.72 m/s²)]*100 %

<u>Percent Difference = 2.47%</u>

<u></u>

<u>(2)</u>

Percent Error = (|Measured Value - Original Value|/Original Value)*100%

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Percent Error (9.96 m/s²) = (|9.96 m/s² - 9.8 m/s²|/9.8 m/s²)*100%

<u>Percent Error (9.96 m/s²) = 1.63 %</u>

Now,

Percent Error (9.72 m/s²) = (|9.72 m/s² - 9.8 m/s²|/9.8 m/s²)*100%

<u>Percent Error (9.72 m/s²) = 0.82 %</u>

<u></u>

<u>(</u>3<u>)</u>

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Mean = (9.96 m/s² + 9.72 m/s²)/2

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Therefore,

Percent Error (Mean) = (|9.84 m/s² - 9.8 m/s²|/9.8 m/s²)*100%

<u>Percent Error (Mean) = 0.41 %</u>

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