If you're on the road in car 2 going 20 m/s and car 1 is going 25 m/s in the dafne direction it would look as if it was passing you at 5 m/s west. This is because 25 m/s - 20 m/s = 5 m/s
You have said that 15cm³ of gold weighs 2.8N. So I may infer that each cm³
of gold weighs about 0.19N. When I compare that figure with the 0.13N per cm³
of mercury, it becomes immediately apparent that the gold is more dense than
mercury. Therefore, the sample of gold, no matter what its size or weight, will
displace its total volume of mercury, and will go on to sink entirely beneath the
waves in the mercury.
The effective mass of the system is 12 kg.
<u>Explanation:</u>
- The effective mass of the system is given by the expression,
= mₓ + 1/2 m₁ + 2/5 m₂
- In the above equations the subscript x denotes block B and the subscript 2 denotes the mass of the solid sphere and the subscript 1 denotes the pulley.
- Expressing the above functions with the data given below. we have,
= 6 kg + 1/2 (4 kg) + 2/5 (10 kg)
= 12 kg.
with the findings above we can conclude that the effective mass of the system is 12 kg
Answer:
The toy's energy is 18 J.
Explanation:
We have, a 4 kg toy is lifted off the ground and falls at 3 m/s. It is required to find toy's energy.
The toy will have kinetic energy due to its motion. The energy is given by :
So, the toy's energy is 18 J.
Answer:
Explanation:
From the question we are told that:
Mass 
Potential difference 
Magnitude 
Generally the equation for Velocity is mathematically given by
Generally the equation for Force is mathematically given by
Where
Therefore
