Astronauts on a distant planet set up a simple pendulum of length 1.2 m. The pendulum executes simple harmonic motion and makes
100 complete vibrations in 280 s. What is the magnitude of the acceleration due to gravity on this planet
1 answer:
Answer:
If you use P = 2 * pi * (L / g)^1/2 for the period of the simple pendulum
g = 4 * pi^2 * 1.2 / 2.8^2 = 6.04 m/s2
Note: omega = 2 pi * f = 2 pi / P and omega = (g / L)^1/2
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