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dolphi86 [110]
3 years ago
11

Astronauts on a distant planet set up a simple pendulum of length 1.2 m. The pendulum executes simple harmonic motion and makes

100 complete vibrations in 280 s. What is the magnitude of the acceleration due to gravity on this planet
Physics
1 answer:
Iteru [2.4K]3 years ago
7 0

Answer:

If you use P = 2 * pi * (L / g)^1/2  for the period of the simple pendulum

g = 4 * pi^2 * 1.2 / 2.8^2 = 6.04 m/s2

Note: omega = 2 pi * f = 2 pi / P  and omega = (g / L)^1/2

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When two point charges are a distance d apart, the magnitude of the electrostatic force between them is F. If the distance betwe
EastWind [94]

Answer:

The magnitude of the electrostatic force decreases by a factor 9

Explanation:

The electrostatic force between two charges is given by:

F=k\frac{q_1 q_2}{d^2}

where

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We see that the magnitude of the force is inversely proportional to the square of the distance. If the distance is increased to 3d: d' = 3d, the new electrostatic force would be:

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So, the electrostatic force decreases by a factor 9.

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3 years ago
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kumpel [21]

Answer:

I'm Pretty sure the answer your looking for is C

4 0
3 years ago
How high was a brick dropped from if if falls in 2.5 seconds?
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Using the kinematic equation d =  V_0 * t  + 1/2 * a * t^2, where d is height you can rewrite this to be d = 1/2*g*t^2 or 4.9t^2
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