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3 years ago

A shopping cart with two nice kids, rolls off a horizontal roof ledge that is 50

Physics

2 answers:

Alisiya [41]3 years ago

8 0

Answer:

9.39 m/s

Explanation:

Using the y-direction, we can solve for the time t it takes for the cart to reach the ground.

Assume the up direction is positive and the down direction is negative.

v₀ = 0 m/s
a = -9.8 m/s²
Δy = -50 m
t = ?

Find the constant acceleration equation that contains these four variables.

Δy = v₀t + 1/2at²

Substitute known values into this equation.

-50 = (0)t + 1/2(-9.8)t²

Multiply and simplify.

-50 = -4.9t²

Divide both sides of the equation by -4.9.

10.20408163 = t²

Square root both sides of the equation.

t = 3.194382825

Now we can use this time t and solve for v₀ in the x-direction. Time is most often our link between vertical and horizontal components of projectile motion.

List out known variables in the x-direction.

v₀ = ?
t = 3.194382825 s
a = 0 m/s²
Δx = 30 m

Find the constant acceleration equation that contains these four variables.

Δx = v₀t + 1/2at²

Substitute known values into the equation.

30 = (v₀ · 3.194382825) + 1/2(0)(3.194382825)²

Multiply and simplify.

30 = v₀ · 3.194382825

Divide both sides of the equation by 3.194382825.

v₀ = 9.391485505

The cart was rolling at a velocity of 9.39 m/s (initial velocity) when it left the ledge.

Dmitry [639]3 years ago

4 0

Answer:

9.39 m/s

Explanation:

Using the y-direction, we can solve for the time t it takes for the cart to reach the ground.

Assume the up direction is positive and the down direction is negative.

v₀ = 0 m/s

a = -9.8 m/s²

Δy = -50 m

t = ?

Find the constant acceleration equation that contains these four variables.

Δy = v₀t + 1/2at²

Substitute known values into this equation.

-50 = (0)t + 1/2(-9.8)t²

Multiply and simplify.

-50 = -4.9t²

Divide both sides of the equation by -4.9.

10.20408163 = t²

Square root both sides of the equation.

t = 3.194382825

Now we can use this time t and solve for v₀ in the x-direction. Time is most often our link between vertical and horizontal components of projectile motion.

List out known variables in the x-direction.

v₀ = ?

t = 3.194382825 s

a = 0 m/s²

Δx = 30 m

Find the constant acceleration equation that contains these four variables.

Δx = v₀t + 1/2at²

Substitute known values into the equation.

30 = (v₀ · 3.194382825) + 1/2(0)(3.194382825)²

Multiply and simplify.

30 = v₀ · 3.194382825

Divide both sides of the equation by 3.194382825.

v₀ = 9.391485505

The cart was rolling at a velocity of 9.39 m/s (initial velocity) when it left the ledge.

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Answer:

may experience a magnetic force, but its speed will not change.

Explanation:

A charged particle moving in a static uniform magnetic field experiences a magnetic force (called Lorentz force) which is given by:

$F=qvB sin \theta$

where

q is the charge

v is the speed of the particle

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$\theta$ is the angle between the direction of the motion of the charge and the direction of the magnetic field

We can notice that when $\theta=0$ (so, when the particle is moving parallel to the field), the magnetic force is zero, so the particle does not experience any force. This means that we can immediately exclude the following choice:

- will always experience a magnetic force, regardless of its direction of motion.

Moreover, the magnetic force acts perpendicular to the direction of motion of the particle. This means it will change the direction of motion of the particle, so we can also exclude the following option

- may experience a magnetic force, but its direction of motion will not change.

Finally, the fact that the magnetic force is perpendicular to the direction of motion of the particle also implies that the force does no work on the particle. According to the work-energy theorem (which states that the kinetic energy gained by the particle is equal to the work done on it), this implies that the particle gains no kinetic energy, so its speed does not change. This allows us to exclude also the following choice

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Therefore, the correct option is the only one remained:

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