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GuDViN [60]
3 years ago
7

HOW FAR IS THE MOON? [COVER UP QUESTION BORED}

Physics
2 answers:
Bad White [126]3 years ago
4 0

238,900 miles exactly

denis-greek [22]3 years ago
3 0

Hi there!

From planet Earth, the moon is about 238,900 miles away from us. It's really far!

I'm glad I was able to help!

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You hold a ruler that has a charge on its tip 6 cm above a small piece of tissue paper to see if it can be picked up. The ruler
Fed [463]

Answer:

9.81 × 10⁻¹⁰ C

Explanation:

Given:

Distance between the tissue and the tip of the scale, r = 6 cm = 0.06 m

Charge on the ruler, Q = - 12 μC = - 12 × 10⁻⁶ C

Mass of the tissue = 3 g = 0.003 Kg

Now,

The force required to pick the tissue, F = mg

where, g is the acceleration due to gravity

also,

The force between (F) the charges is given as:

F=\frac{kQq}{r^2}

where,

q is the charge on the tissue

k is the Coulomb's constant = 9 × 10⁹ Nm²/C²

thus,

mg=\frac{kQq}{r^2}

on substituting the respective values, we get

0.003\times9.81=\frac{9\times10^9\times(-12\times10^{-6})\times q}{0.06^2}

or

q = 9.81 × 10⁻¹⁰ C

Minimum charge required to pick the tissue paper is 9.81 × 10⁻¹⁰ C

3 0
3 years ago
You pull a 70-kg crate at an angle of 30° above the horizontal. If you pull with a force of 600N and the coefficient of kinetic
Alenkinab [10]

Answer:

Explanation:

Force of friction acting on the body = μ mg cosθ

= .4  x 70 x 9.8 x cos30

= 237.63 N

component of weight = mgsinθ

= 70 x 9.8 x sin30

= 343 N  

Net upward force = 600 - mgsinθ - μ mg cosθ

= 600 - 343 - 237.63

= 105.37 N

acceleration in upward direction = 105.37 / 70

= 1.5 m /s²

s = ut + 1/2 a t²

= 0 + .5 x 1.5 x 3²

= 6.75 m .

5 0
3 years ago
In a mall, a shopper rides up an escalator between floors. At the top of the escalator, the shopper turns right and walks 6.40 m
Elden [556K]

Answer:

25 degrees above the horizontal.

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3 years ago
The diagram shows a swinging pendulum.
pashok25 [27]

Answer:

A. The mechanical energy transforms to thermal energy as the pendulum slows and eventually stops moving.

Explanation:

took the quiz on edge

8 0
3 years ago
Read 2 more answers
How to find the gradient of a velocity time graph
Sidana [21]
The area-

The area under the line in a velocity-time graph represents the distance travelled. To find the distance travelled in the graph above, we need to find the area of the light-blue triangle and the dark-blue rectangle.

<span><span>Area of light-blue triangle -
<span>The width of the triangle is 4 seconds and the height is 8 meters per second. To find the area, you use the equation: <span>area of triangle = 1⁄2 × base × height </span><span>so the area of the light-blue triangle is 1⁄2 × 8 × 4 = 16m. </span></span></span><span> Area of dark-blue rectangle The width of the rectangle is 6 seconds and the height is 8 meters per second. So the area is 8 × 6 = 48m.</span><span> Area under the whole graph <span>The area of the light-blue triangle plus the area of the dark-blue rectangle is:16 + 48 = 64m.<span>This is the total area under the distance-time graph. This area represents the distance covered.</span></span></span></span>
7 0
4 years ago
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