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natita [175]
3 years ago
11

A wheel of radius 30 cm is rotating at a rate of 2.0 revolutions every 0.080 s. (A) through what angle, in radians, does the whe

el rotate in 1.0 s? (B) what is the linear speed of a point on the wheel's rim? (C) what is the wheel's frequency of rotation?
Physics
1 answer:
ioda3 years ago
7 0

You said 2 revolutions every 0.08 seconds

1 revolution = 2pi radians.

A). The 'unit rate' is    (2 rev) x (2pi / 0.08 sec)  = 50pi radians/sec. =

                                                       157.1 radians per sec (rounded)

B). Radius of the wheel = 30 cm
     Circumference = 2pi R = 60pi cm = 188.5 cm (rounded)

     Rotation speed = 2 revs per 0.08 sec
     Linear speed =    2 x 60pi cm per 0.08 sec

                               (120pi cm) / (0.08 sec) = 47.12 meters per sec

C). Frequency = (revs) per second

                        = (2) / (0.08 sec) = 25 per second .   

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Answer A an Open Universe

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5 0
3 years ago
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A particular balloon can be stretched to a maximum surface area of 1257 cm2. The balloon is filled with 3.1 L of helium gas at a
chubhunter [2.5K]

Answer:

The ballon will brust at

<em>Pmax = 518 Torr ≈ 0.687 Atm </em>

<em />

<em />

Explanation:

Hello!

To solve this problem we are going to use the ideal gass law

PV = nRT

Where n (number of moles) and R are constants (in the present case)

Therefore, we can relate to thermodynamic states with their respective pressure, volume and temperature.

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} --- (*)

Our initial state is:

P1 = 754 torr

V1 = 3.1 L

T1 = 294 K

If we consider the final state at which the ballon will explode, then:

P2 = Pmax

V2 = Vmax

T2 = 273 K

We also know that the maximum surface area is: 1257 cm^2

If we consider a spherical ballon, we can obtain the maximum radius:

R_{max} = \sqrt{\frac{A_{max}}{4 \pi}}

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Vmax = 4 190.05 cm^3 = 4.19 L

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P_{max} = P_1 \frac{V_1T_2}{V_2T_1}

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6 0
3 years ago
12
Svet_ta [14]

Answer:

See below ~

Explanation:

An object will sink in water when its density is greater than that of water, which is 1 g/cm³.

Volume of the box is <u>1331 cm³</u>. (11³)

Maximum mass of sand will be 1331 g. [because 1331/1331 = 1 g/cm³]

  • Volume of sand = Mass of sand / Density of sand
  • Volume (sand) = 1331/3.5
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If the volume of sand is <u>greater than 380.29 cm³</u>, the box will sink in water.

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3 years ago
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Nikitich [7]
You can tell a lot about an object that's not moving,
and also a lot about the forces acting on it:

==> If the box is at rest on the table, then it is not accelerating.

==> Since it is not accelerating, I can say that the forces on it are balanced.

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Vertical forces:
gravitational force (weight of the box, pulling it down)
normal force (table pushing the box up)

All of the forces on this list must add up to zero, so ...

(Gravitational force down) + (normal force up) = zero

(Gravitational force down) = -(normal force up) .
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11Alexandr11 [23.1K]

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Explanation:

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