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Triss [41]
3 years ago
6

Trapezoid MNPQ is similar to Trapezoid RSTU. What is the length of the "x" on the misside side NP ? Also, what is the length of

"y" on the missing side TU?
Mathematics
1 answer:
ivolga24 [154]3 years ago
8 0

Answer:

x =  15

y =  25

Step-by-step explanation:

Given

See attachment for MNPQ and RSTU

Required

Find x and y

To solve this question, we make use of equivalent ratios of corresponding side lengths.

The ratio of corresponding sides are:

MN : RS

NP : ST

PQ : TU

MQ : RU

From the attachment, we have:

MN : RS \to 18 : 30

NP : ST \to x : 25

PQ : TU \to 15 : y

To solve for x, we equate MN : RS and NP : ST

18 : 30 = x : 25

Express as fraction

\frac{18 }{ 30 }= \frac{x }{ 25}

Make x the subject

x =  25 * \frac{18 }{ 30 }

x =  \frac{25 * 18 }{ 30 }

x =  \frac{450}{ 30 }

x =  15

To solve for y, we equate MN : RS and PQ : TU

18 : 30 = 15 : y

Express as fraction

\frac{18 }{ 30 }= \frac{15 }{ y}

Make y the subject

y = 15 * \frac{30 }{ 18 }

y =  \frac{15 *30}{ 18 }

y =  \frac{450}{ 18 }

y =  25

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Answer:

The probability of the sample mean foot length less than 23 cm is 0.120

Step-by-step explanation:

* Lets explain the information in the problem

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∴ The sample mean x = 23, find the standard deviation σx

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∵ σ = 1.7 and n = 25

∴ σx = 1.7/√25 = 1.7/5 = 0.34

- Now lets find the z-score using the rule z-score = (x - μ)/σx

∵ x = 23 , μ = 23.4 , σx = 0.34

∴ z-score = (23 - 23.4)/0.34 = -1.17647 ≅ -1.18

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∴ P(X < 23) = 0.119 ≅ 0.120

* The probability of the sample mean foot length less than 23 cm is 0.120

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3 years ago
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Let d be the common difference between terms in the sequence \{a_n\}_{n\ge1}. Then

a_{19}=-58
a_{20}=a_{19}+d
a_{21}=a_{19}+2d
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The first term in the sequence, a_1, satisfies

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