1) Let f(x) be x^3+5x^2+2x+1
Since f(x) is divided by x+1,
R= f(-1) = (-1)^3 + 5(-1)^2+2(-1) + 1
= -1+5-2+1
= 3
2) Let f(x) be x^3 - 6x + 5x +2
Since f(x) is divided by x-5,
R= f(5) = x^3 - 6x^2 + 5x +2
= 5^3 - 6(5)^2 + 5(5) +2
= 125 - 150 + 25 + 2
= 2
Answer:
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Step-by-step explanation:
Answer:
x = - 5 , x =
Step-by-step explanation:
the values of x that make f(x) zero are the zeros
to find the zeros let f(x) = 0 , that is
3x² + 13x - 10 = 0
consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 3 × - 10 = - 30 and sum = + 13
the factors are + 15 and - 2
use these factors to split the x- term
3x² + 15x - 2x - 10 = 0 ( factor the first/second and third/fourth terms )
3x(x + 5) - 2(x + 5) = 0 ← factor out (x + 5) from each term
(x + 5)(3x - 2) = 0
equate each factor to zero and solve for x
x + 5 = 0 ⇒ x = - 5
3x - 2 = 0 ⇒ 3x = 2 ⇒ x =
Answer:
First statement: Angles 1 and 3 are vertical angles.
First reason: Definition of supplementary
Second Reason: Vertical angles are congruent
Third Reason: Vertical Angles Theorem
Step-by-step explanation:
Hope this helps: Angles that form an X- Type figure are congruent.
Answer:
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