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klasskru [66]
2 years ago
5

Which expression is equivalent to 1/3 y?

Mathematics
2 answers:
SSSSS [86.1K]2 years ago
6 0

Answer:

1/3y+1/3(6-y)

MrMuchimi2 years ago
3 0

Answer:

The answer is 1/6y+1/6(y+12)-2

Step-by-step explanation:

I used a math calculator.

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Riley has a farm on a rectangular piece of land that is 200200200 meters wide. This area is divided into two parts: A square are
777dan777 [17]

Answer:

The inequality that models the situation for her to have money to save is

7L² > 3(200L - L²)

On simplifying and solving,

L > 60 meters

Step-by-step explanation:

The length of her farm = L meters

The farm where she grows avocados is of square dimension

Area of the farm = L × L = L²

The piece of land is 200 m wide.

Total area of the piece of land = 200 × L = (200L) m²

If the area of her farm = L²

Area of the side where she lives will be

(Total area of the land) - (Area of the farm)

= (200L - L²)

= L(200 - L)

Every week, Riley spends $3 per square meter on the area where she lives, and earns $7 per square meter from the area where she grows avocados.

Total amount she earns from the side she grows the avocados = 7 × L² = 7L²

Total amount she spends on the side where she lives = 3 × (200L - L²) = 3(200L - L²)

For her to save money, the amount she earns must be greater than the amount she spends, hence the inequality had to be

(Amount she earns) > (Amount she spends)

7L² > 3(200L - L²)

To simplify,

7L² > 3L(200 - L)

Since L is always positive, we can divide both sides by L

7L > 3(200 - L)

7L > 600 - 3L

10L > 600

L > 60 meters

Hope this Helps!!!

7 0
3 years ago
1.) what is five forths of a right angle, 2.) what is three forths of a right angle?
klasskru [66]

Answer:

1.) 112.5 degrees

2.) 67.5 degrees

3.) 150 degrees

4.) 240 degrees

5.) 540 degrees

( don't hate me if any is wrong don't think they are but just trying to help) let me know if any of them are wrong and if it helped!

3 0
3 years ago
Read 2 more answers
A rectangular pyramid has a height of 8 meters. The base is 7 meters in length and 15 meters in width two different triangular c
vagabundo [1.1K]

Answer:

The difference in the areas of the cross section is 32 m²

Step-by-step explanation:

The given parameters are;

The height of the rectangular pyramid = 8 meters

The length of the base of the pyramid = 7 meters

The width of the base of the pyramid = 15 meters

Whereby triangular cross sections are formed through the vertex and perpendicular to the base, and to each other, we have;

The sides of the two triangles consists of the following;

1) Two slant height of the pyramid each

2) The two perpendicular lines joining the midpoints of the opposite sides of the base of the pyramid with length equal to the length of the adjacent side to the sides from which they are drawn which are 15 meters and 7 meters

3) The two lines and the corresponding slant height form triangles cross section which are perpendicular to each other.

the slant height, h_l, is given as follows;

h_l = √(8² + (15/2)²) ≈ 10.966

For the triangular cross section with base = 15 m

The area of the cross section = 1/2 × Base₁₅ × Height = 1/2 × 15 m × 8 m = 60 m²

For the triangular cross section with base = 7 m

The area of the cross section = 1/2 × Base₇ × Height = 1/2 × 7 m × 8 m = 28 m²

The difference in the areas of the cross section = 60 m² - 28 m² = 32 m².

5 0
3 years ago
An observer took a time-exposure photograph of polaris and five nearby stars. how many hours were required to show their star pa
olga55 [171]
Photographing stars requires you to keep your exposure open for a long time. Taking pictures of star trails would take about 30 minutes to three hours. If you multiply that for the 6 stars stated above in the problem then you would be needing that much time if the stars were close and approximately 3 to 18 hours capture their star trails if they were far apart from each other.
5 0
3 years ago
Convert this equation to standard form: y=1/2x + 2/3
dsp73
The answer would be,
-  \frac{1}{2}x + y =  \frac{2}{3}
Hope this helped
:D
7 0
3 years ago
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