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3 years ago

Repetitive motion can cause injury.

Physics

2 answers:

zlopas [31]3 years ago

4 0

Answer:

Explanation:

ig pybrothepyro4

marin [14]3 years ago

3 0

It is True because hitting your head 20 time will cause problems

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For an object to be classified as a ____, it must meet certain definite criteria: It must be massive enough to pull itself into

Orlov [11]

Answer:

a planet

Explanation:

a planet is one which exerts these properties and therefore is the answer

5 0

4 years ago

The position of a ball as a function of time is given by

Andre45 [30]

Answer:

x = -6.5 meters

Explanation:

The position of a ball as a function of time t is given by :

$x=3\ m+(-5\ m/s)t$ ..................(1)

Where t is time in seconds

We need to find the position of the ball at 1.9 s. It can be simply calculated putting t = 1.9 s in equation (1) as :

$x=3+(-5)(1.9)$

x = -6.5 meters

So, the position of the ball at 1.9 seconds is -6.5 meters. Hence, this is the required solution.

6 0

4 years ago

How much heat must be removed from 200 pounds of blanched vegetables at 189 degrees F to freeze them to a temperature of 22 degr

Virty [35]

To solve this problem it is necessary to apply the concepts related to heat exchange in the vegetable and water.

By definition the exchange of heat is given by

$Q =mc\Delta T$

where,

m = mass

c = specific heat

$\Delta T$ = Change in temperature

Therefore the total heat exchange is given as

$\Delta Q = Q_w+Q_v$

$\Delta Q = m_wc_w(T_i-T_f)+m_vc_v(T_i-T_f)$

Our values are given as,

Total mass is $M_T$ = 200lb ,however the mass of solid vegetable and water is given as,

$m_v= 0.4*200lb = 80lb$

$m_w=0.6*200lb=120lb$

$T_i = 183\°F\\T_f = 22\°F\\c_w = 1Btu/lbF\\c_v = 0.24Btu/lbF$

Replacing at our equation we have,

$\Delta Q = m_wc_w(T_i-T_f)+m_vc_v(T_i-T_f)$

$\Delta Q = (120)(1)(183-22)+(80)(0.24)(183-22)$

$\Delta Q = 22411.2Btu$

Therefore the heat removed is 22411.2 Btu

6 0

3 years ago

First consider a Carnot engine that operates between a hot reservoir at 58°C and a cold reservoir at -17°C. In running 24 minute

jok3333 [9.3K]

Answer:

Explanation:

Given that,

Hot reservoir temperature is

TH = 58°C

TH = 58 + 273 = 331 K

Cold reservoir temperature

TC = -17°C

TC = -17°C + 273 = 256K

In 24minutes 590 J of heat was removed from hot reservoir

t = 24mins

t = 24 × 60 = 1440 seconds

Then,

Power is given as

P = E / t

P = 590 / 1440

P = 0.41 W

Since this removed from the hot reservoir, then, QH = 0.41W

We want to find heat expelled to the cold reservoir QX

Efficiency is given as

η = 1 - TH/TC = 1 - QH/QC

1 - TH/TC = 1 - QH/QC

TH/TC = QH/QC

Make QC subject of formula

QC = QH × TC / TH

QC = 0.41 × 256 / 331

QC = 0.317 W

7 0

3 years ago

A speed does not involve the element of

guajiro [1.7K]

A speed does not involve the element of direction.

6 0

3 years ago