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3 years ago

Strip electrons from an atom and the atom becomes a

Physics

2 answers:

Dafna11 [192]3 years ago

7 0

It becomes a positive Iron

Elanso [62]3 years ago

4 0

It becomes a positive ion

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5. Kelvin applied a rightward force of 302 N to a 29 kg desk to accelerate it across the floor. The

Naddik [55]

The force of friction is 213.2 N

Explanation:

The frictional force acting on an object sliding on a surface is given by:

$F_f = \mu mg$

where:

$\mu$ is the coefficient of friction

m is the mass of the object

g is the acceleration of gravity

In this problem we have

$\mu=0.750$

m = 29 kg

$g=9.8 m/s^2$

Therefore, the force of friction is

$F_f = (0.750)(29)(9.8)=213.2 N$

Learn more about friction:

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3 0

3 years ago

H. The length of the shadow is different in evening and in the day. Justify

Vinvika [58]

the shadows are exactly the same length in the morning as they are in the evening.

is so obvious it’s that when the sun is low you get long shadows and when the sun is up in the sky like in the noon the shadow is shorter.

3 0

3 years ago

Read 2 more answers

What is the most common kind of element in the solar wind?

eimsori [14]

OzsnuhgnowgnwrfoqingoiwrgWWR KEFQF QEFI FBI O8QE VU F8EINFOQIHWJ OU JN K kjbJ IUJ j osd sfljvbwj 9 oirs jf bhfb wjsf jfow vj isfobsfjb io jio ofsjb

8 0

3 years ago

When you ride a bike and make a turn, you can feel your body trying to

Rina8888 [55]

Answer:first law

Explanation:

it states the a body in motion or rest maintain its state until an external force is acted on it

8 0

3 years ago

A shell is fired at an angle of 35° above the horizontal at a velocity of 40 m/s. (a) What is it's speed at the highest point of

Fudgin [204]

Answer:

Part a)

$v_f = v_x = 32.77 m/s$

Part b)

T = 4.68 s

Explanation:

Part a)

Shell is fired at speed of 40 m/s at angle of 35 degree

so here we have

$v_x = 40 cos35 = 32.77 m/s$

$v_y = 40 sin35 = 22.94 m/s$

since gravity act opposite to vertical speed of the shell so at the highest point of its trajectory the vertical component of the speed will become zero

so at the highest point the speed is given

$v_f = 32.77 m/s$

Part b)

After completing the motion we know that the displacement of the object will be zero in Y direction

so we have

$\Delta y = 0$

$0 = v_y t - \frac{1}{2}gt^2$

$T = \frac{2v_y}{g}$

$T = \frac{2(22.94)}{9.81} = 4.68 s$

7 0

3 years ago