Answer:
The current through the circuit element will also be doubled.
Explanation:
The relationship between voltage and current of a circuit element is given by Ohm's Law. According to Ohm's Law:
Voltage = (Resistance)(Current)
If the resistance of the element is kept constant, the relation between Voltage and Current through that element becomes as follows:
Voltage = (Constant)(Current)
Voltage α Current
Thus, the voltage is directly proportional to the current for constant value of the resistance.
Therefore, when the voltage across a circuit element of constant resistance is doubled, <u>the current through the circuit element will also be doubled.</u>
Explanation:
a) Given in the y direction (taking down to be positive):
Δy = 50 m
v₀ = 0 m/s
a = 10 m/s²
Find: t
Δy = v₀ t + ½ at²
50 m = (0 m/s) t + ½ (10 m/s²) t²
t = 3.2 s
b) Given in the x direction:
v₀ = 12 m/s
a = 0 m/s²
t = 3.2 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (12 m/s) (3.2 s) + ½ (0 m/s²) (3.2 s)²
Δx = 38 m
ANOTHER RUNNING DOG
Explanation:
In the given question it is to find a suitable reference point to describe the motion of dog. Here I could suggest that it is better to compare the dog with another running dog to create the relative speed difference to get a reliable motion variation.
Because the motion of dog is in the linear with respect to the another dog and to the acceleration produced by the dog in the required interval is easy to calculate with respect to another dog which is already in motion.
Hence, I suggest that Motion of dog can be analysed better by analyse the motion variation of dog with another dog running.
V=0 v²=0, A=v-u/t. T=v-u/a. T= 0-9.32/-4.06 therefore time = 2.296 seconds
