Answer:
1. 57.5%
2. 27.89 g
Explanation:
1. Determination of the percentage of sodium in sodium hydroxide.
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
Mass of Na in NaOH = 23 g
Percentage of Na = mass of Na / Molar mass of NaOH × 100
Percentage of Na = 23/40 × 100
Percentage of Na = 57.5%
2. Determination of the mass of sodium in 48.5 g of sodium hydroxide.
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
Mass of Na in NaOH = 23 g
Total mass of NaOH = 48.5 g
Mass composition of Na = mass of Na / Molar mass of NaOH × Total mass
Mass composition of Na = 23/40 × 48.5
Mass composition of Na = 27.89 g
If the resistance is electrical, then that substance is an 'insulator'.
I believe the best answer is D.
All answers contribute to a machine, if there is an all above choice, chose that.
The total ball pressure is sum of gauge pressure and atmospheric pressure
We know that atmospheric pressure = 101.325 kPa
so the total ball pressure = 61 kPa + 101.325 kPa = 162.325 kPa
Now we will use ideal gas equation as
PV = nRT
P = pressure = 162.325 kPa
V = 5.2 L
R = gas constant = 8.314 kPa L / mol K
T = 32 C = 273.15 + 32 = 305.15 K
n = moles = ?
Moles = PV / RT = 162.325 kPa X 5.2 / 305.15 X 8.314 = 0.332 moles
Answer:
Explanation:
Hello,
In this case, given the law of conservation of mass which states that mass cannot be created nor destroyed, since the produced mass of the compound is 15.9 g and the mass of the initial substance is 12.3 g we obtain the mass of air by applying the following equation:
Thus, solving for the mass of air we obtain:
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