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Andre45 [30]
3 years ago
11

PLS HELP.

Chemistry
1 answer:
Lesechka [4]3 years ago
6 0

Answer:

1. 57.5%

2. 27.89 g

Explanation:

1. Determination of the percentage of sodium in sodium hydroxide.

Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

Mass of Na in NaOH = 23 g

Percentage of Na = mass of Na / Molar mass of NaOH × 100

Percentage of Na = 23/40 × 100

Percentage of Na = 57.5%

2. Determination of the mass of sodium in 48.5 g of sodium hydroxide.

Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

Mass of Na in NaOH = 23 g

Total mass of NaOH = 48.5 g

Mass composition of Na = mass of Na / Molar mass of NaOH × Total mass

Mass composition of Na = 23/40 × 48.5

Mass composition of Na = 27.89 g

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Answer:

Molarityof the solution is 0.1375 M.

Explanation:

We will first find the number of moles of diethyl ether (C4H10O)  by finding its molar mass and measured mass.

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Now, molarity of the solution = Number of moles of diethyl ether / Volume of the solution( in  mL) x 1000 =  \dfrac {0.011}{80}\times 1000 = 0.1375\ M

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