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Andre45 [30]
3 years ago
11

PLS HELP.

Chemistry
1 answer:
Lesechka [4]3 years ago
6 0

Answer:

1. 57.5%

2. 27.89 g

Explanation:

1. Determination of the percentage of sodium in sodium hydroxide.

Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

Mass of Na in NaOH = 23 g

Percentage of Na = mass of Na / Molar mass of NaOH × 100

Percentage of Na = 23/40 × 100

Percentage of Na = 57.5%

2. Determination of the mass of sodium in 48.5 g of sodium hydroxide.

Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

Mass of Na in NaOH = 23 g

Total mass of NaOH = 48.5 g

Mass composition of Na = mass of Na / Molar mass of NaOH × Total mass

Mass composition of Na = 23/40 × 48.5

Mass composition of Na = 27.89 g

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How do you find the amount of moles is .032 grams of water and whats the answer
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Answer:

\boxed {\boxed {\sf 0.0018 \ mol \ H_2 O }}

Explanation:

First, we need to find the molecular mass of water (H₂O).

H₂O has:

  • 2 Hydrogen atoms (subscript of 2)
  • 1 Oxygen atom (implied subscript of 1)

Use the Periodic Table to find the mass of hydrogen and oxygen. Then, multiply by the number of atoms of the element.

  • Hydrogen: 1.0079 g/mol
  • Oxygen: 15.9994 g/mol

There are 2 hydrogen atoms, so multiply the mass by 2.

  • 2 Hydrogen: (1.0079 g/mol)(2)= 2.0158 g/mol

Now, find the mass of H₂O. Add the mass of 2 hydrogen atoms and 1 oxygen atom.

  • 2.0158 g/mol + 15.9994 g/mol = 18.0152 g/mol

Next, find the amount of moles using the molecular mass we just calculated. Set up a ratio.

0.032 \ g  \ H_2 O* \frac{ 1 \ mol \ H_2 O}{18.0152 \ g \ H_2 O}

Multiply. The grams of H₂O will cancel out.

0.032 * \frac{1 \ mol \ H_2 O}{18.0152 }

\frac{0.032 *1 \ mol \ H_2 O}{18.0152 }

0.00177627781 \ mol \ H_2 O

The original measurement given had two significant figures (3,2). We must round to have 2 significant figures. All the zeroes before the 1 are not significant. So, round to the ten thousandth.

The 7 in the hundred thousandth place tells us to round up.

0.0018 \ mol \ H_2 O

There are about <u>0.0018 moles in 0.032 grams.</u>

6 0
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