Answer: 2 grams
Explanation:
chemical formula of C6H:
C6H
relative atomic mass of
C:12
H:1
C6:72
H1:12
relative formula mass of
C6H1=73
molar mass of glucose:
73g
the molar mass is the mass of one mole of a substance.
in
26.2g
of C6H there are
26.2 divide by 73g moles present.
there are 0.358 or 35.8*10-1
I gram of NH3 is 17.03052
2 grams of NH3 is 35
There are 2 valence elcetrons
The answer is B hope this is right
Answer: Bismuth (Bi) , Nitrogen family
Explanation:
As the element has 5 valence electrons in the sixth energy level, which mens it belongs to 6th period as the valence electron has entered the 6th energy level.
Now as the electrons are filled according to afbau's rule , the electronic configuration of the element will be :
![[Xe]4f^{14}5d^{10}6s^26p^3](https://tex.z-dn.net/?f=%5BXe%5D4f%5E%7B14%7D5d%5E%7B10%7D6s%5E26p%5E3)
Now as the atomic number of element is equal to the number of electrons in a neutral atom , the atomic number is 83 and the element is Bismuth (Bi). As the last electron enters p -subshell , it is a p block element. It lies in group 15 which is nitrogen family.
Answer:
% sodium= 13.6 % sodium
% carbon= 35.5 % carbon
% hydrogen= 4.7% hydrogen
% nitrogen = 8.3% nitrogen
% oxygen = 37.8 % oxygen
Explanation:
To find its percent composition means that we are to find to find the percentage of each of the constituents of the compound present.
The molar mass of monosodium glutamate is 169.11 gmol-1
Hence;
Percent of sodium= 23 gmol-1/169.11 gmol-1 × 100 = 13.6 % sodium
Percent of Carbon= 60 gmol-1/169.11 gmol-1 ×100 = 35.5 % carbon
Percent of hydrogen= 8/169.11 gmol-1 ×100 = 4.7% hydrogen
Percent nitrogen = 14/169.11 gmol-1 × 100 = 8.3% nitrogen
Percent oxygen = 64/169.11 gmol-1 ×100 = 37.8 % oxygen
