So assuming that each student chose only one sport or 'other', add the percents and subtract from 100
37.5+40=77.5
100-77.5=22.5
22.5%=other
18 students=22.5%
divide both sides by 22.5
0.8=1%
therfor
100%=80
80 students participated
futbol=37.5% of 80=0.375 times 80=30
30 picked football
25%
Divide 12 by 3 and you'll get 4.
That means 1/4 or a quarter of the 12 is 3.
(Convert the fraction to its percentage form)
1/4 or 1 divided by 4 equals 0.25
Multiply 0.25 by 100 and you'll get 25%
X + y = 3,500 . . . (1)
x – y = 2,342 . . . (2)
(1) - (2) => 2y = 1158
y = 1158/2 = 579
x = 3500 - 579 = 2921
Therefore, he had 2,921 contempolary titles and 579 classic titles.
