Always use least amount of sig figs possible. So this 9.7 would be (answer): 2 sig figs
Answer:
10.1 g of Al are formed
Explanation:
The reaction is:
2AlCl3 --> 2Al + 3Cl2
So 2 moles of aluminun chloride decompose into 2 moles of Al and 3 moles of chlorine.
Ratio is 2:2.
Let's convert the mass of salt into moles (mass / molar mass)
50 g / 133.34 g/mol = 0.374 moles.
As the ratio is 2: 2, if I have 0.374 moles of salt, I would produce the same amount of Al, just 0.374.
Let's convert the moles to mass
(Mol . molar mass)
0.374 mol . 26.98 g / mol = 10.1 g of Al are formed
Ξ
Answer:
MgSO4. 7H2O
There are seven water molecules attached to the hydrated salt.
Explanation:
From the equation;
Number of moles of hydrated salt = number of moles of anhydrous salt, we obtain:
Mass of hydrated salt/ molar mass of hydrated salt = mass of anhydrous salt/ molar mass of anhydrous salt
From the question;
Mass of hydrated salt = 1.000g
Molar mass of hydrated salt = 120.366 +18x gmol-1
Mass of anhydrous salt= 0.488g
Molar mass of anhydrous salt= 120.366 gmol-1
Substituting into the equation above;
1.000/120.366 +18x = 0.488/120.366
1.000/120.366 +18x = 0.004
1.000= 0.004 (120.366 +18x)
1.000= 0.48 + 0.072x
1.000 - 0.48 = 0.072x
0.52= 0.072x
x= 0.52/0.072
x=7
Therefore the hydrated salt is MgSO4. 7H2O
Answer:
Major organic products are- (a) propan-1-ol and (b) 2-methylpropan-2-ol
Explanation:
methyl magnesium bromide gives nucleophilic addition reaction with carbonyl group. Because methyl magnesium bromide is a strong nucleophile and carbonyl group is a strong electrophilic center.
Propanal contains an aldehyde group and propanone contains a ketone group. hence they both give nucleophilic addition with methyl magnesium bromide.
Dilute acid is added to protonate the alkoxide produced during nucleophilic addition.
Reactions are shown below.
