F(x)=0
f(x)=y
so where y=0, the x value is the x in f(x)
basically, where the line crosses or touches the x axis, those ar the x values that make the function true
(4x + 3y)² =
<span>(4x)² + 2 (4x) (3y) + (3y)² = </span>
<span>16x² + 24xy + 9y²</span>
The answer is x≤<span><span>−<span>2y</span></span>+<span>200</span></span>
