Find the range of the balances for the 5 day period

Find the equation of the line that passes through the point (-3,-6) and is parallel to the line y=-4/3x+7/3

Rufina [12.5K]

Answer: The answer is y=-4/3x-10.

Step-by-step explanation:

-6=-4/3(-3)+b

-6=4+b

-4 -4

-10=b

y=-4/3x-10

7 0

3 years ago

Calculate the value <br><br>X + 20<br>3x + 10<br>5x +10°

Serga [27]

Answer:

x + 20° = 35.56°

3x + 10° = 56.68°

5x + 10° = 87.8°

Step-by-step explanation:

Assume;

Given measures are angle of a triangle

x + 20°

3x + 10°

5x + 10°

Find:

Value of each angle

Computation:

We know that, sum of all interior angle in a triangle is 180°

So,

We say that

x + 20° + 3x + 10° + 5x + 10° = 180°

9x + 40° = 180°

9x = 140°

x = 15.56°

So,

x + 20° = 15.56 + 20 = 35.56°

3x + 10° = 3(15.56) + 10 = 56.68°

5x + 10° = 5(15.56) + 10 = 87.8°

6 0

3 years ago

Plz Help, Will give brainliest

masya89 [10]

Step-by-step explanation:

By AAS congruence, triangles RNM and RNP are congruent. Hence 7x = 2x + 25, x = 5.

Line RM = 7x = 7(5) = 35 units.

5 0

3 years ago

I tell you these facts about a mystery number, $c$: $\bullet$ $1.5 < c < 2$ $\bullet$ $c$ can be written as a fraction wit

makkiz [27]

Answer:

Possible answer: $\displaystyle c = \frac{16}{10} = \frac{8}{5} = 1.6$ .

Step-by-step explanation:

Rewrite the bounds of $c$ as fractions:

The simplest fraction for $1.5$ is $\displaystyle \frac{3}{2}$ . Write the upper bound $2$ as a fraction with the same denominator:

$\displaystyle 2 = 2 \times 1 = 2 \times \frac{2}{2} = \frac{4}{2}$ .

Hence the range for $c$ would be:

$\displaystyle \frac{3}{2} < c < \frac{4}{2}$ .

If the denominator of $c$ is also $2$ , then the range for its numerator (call it $p$ ) would be $3 < p < 4$ . Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than $2$ .

To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)

$\displaystyle \frac{3}{2} = \frac{2 \times 3}{2 \times 2} = \frac{6}{4}$ .

$\displaystyle \frac{4}{2} = \frac{2\times 4}{2 \times 2} = \frac{8}{4}$ .

At this point, the difference between the numerators is now $2$ . That allows a number ( $7$ in this case) to fit between the bounds. However, $\displaystyle \frac{1}{c} = \frac{4}{7}$ can't be written as finite decimals.

Try multiplying the numerator and the denominator by a different number.

$\displaystyle \frac{3}{2} = \frac{3 \times 3}{3 \times 2} = \frac{9}{6}$ .

$\displaystyle \frac{4}{2} = \frac{3\times 4}{3 \times 2} = \frac{12}{6}$ .

$\displaystyle \frac{3}{2} = \frac{4 \times 3}{4 \times 2} = \frac{12}{8}$ .

$\displaystyle \frac{4}{2} = \frac{4\times 4}{4 \times 2} = \frac{16}{8}$ .

$\displaystyle \frac{3}{2} = \frac{5 \times 3}{5 \times 2} = \frac{15}{10}$ .

$\displaystyle \frac{4}{2} = \frac{5\times 4}{5 \times 2} = \frac{20}{10}$ .

It is important to note that some expressions for $c$ can be simplified. For example, $\displaystyle \frac{16}{10} = \frac{2 \times 8}{2 \times 5} = \frac{8}{5}$ because of the common factor $2$ .

Apparently $\displaystyle c = \frac{16}{10} = \frac{8}{5}$ works. $c = 1.6$ while $\displaystyle \frac{1}{c} = \frac{5}{8} = 0.625$ .

8 0

4 years ago

Read 2 more answers

Find a third degree polynomial that passes through the points (−3, 0),(−2, −3),(0, 3) and (2, −15). Using the form p(x) = ax3+bx

LekaFEV [45]

Answer:

f(x)=3/16x^3-9/4x+3

7 0

3 years ago