1. This is a combustion reaction.<span>
<span>Combustion reactions can happen with the </span>presence of O</span>₂ <span>gas. O₂<span>
reacts with another element or compound and </span></span>oxidize<span> it. Here ethanol reacts with O₂<span> and produces </span></span>CO₂ and H₂O as products.<span> <span>Combustion is also called as </span></span>burning. <span>
2.
Reaction will shift to right. <span>
</span><span>If more CH</span>₃CH₂OH is added to the system, then the</span> amount of CH₃CH₂OH will increase.<span> <span>Then the equilibrium in the system </span></span>will be broken.<span> <span>To make the equilibrium again, the </span></span>added CH₃CH₂OH should be removed.<span> To do that system will consume more CH</span>₃CH₂<span>OH to make products which helps to decrease
the amount of ethanol. Hence,
the reaction will shift to right.<span>
3. The reaction
will shift to right.</span><span>
</span><span>If the water is extracted from the system, the </span>amount of water will decrease. <span>That means the </span>amount of products decrease. Then the system will try to gain equilibrium by increasing the water. To increase water the forward reaction should be enhanced. <span>Hence, the</span> reaction will shift to right.<span>
4. The reaction
will shift to right.
</span><span>This is an </span>exothermic reaction <span>since it </span>produces heat. If the produced heat is removed, then the system will be cold. To maintain the temperature, system has to increase the amount of heat produced. Then, the forward reaction should be
enhanced. Hence, the reaction
will shift to right.<span>
5. The Le
Chatelier's principle.
</span>Le Chatelier's principle says if a
condition changes in a system which was in an equilibrium state, the system
will try to gain equilibrium by correcting the changed condition back to
normal. Most of industries which make
chemicals use this principle</span>
Answer:
Energy is released.
Explanation:
When an electron absorbs energy, it moves up into an excited state. When it releases energy, it will return to the ground state.
The correct Answer for this question is D
<h3>
Answer:</h3>
0.111 J/g°C
<h3>
Explanation:</h3>
We are given;
- Mass of the unknown metal sample as 58.932 g
- Initial temperature of the metal sample as 101°C
- Final temperature of metal is 23.68 °C
- Volume of pure water = 45.2 mL
But, density of pure water = 1 g/mL
- Therefore; mass of pure water is 45.2 g
- Initial temperature of water = 21°C
- Final temperature of water is 23.68 °C
- Specific heat capacity of water = 4.184 J/g°C
We are required to determine the specific heat of the metal;
<h3>Step 1: Calculate the amount of heat gained by pure water</h3>
Q = m × c × ΔT
For water, ΔT = 23.68 °C - 21° C
= 2.68 °C
Thus;
Q = 45.2 g × 4.184 J/g°C × 2.68°C
= 506.833 Joules
<h3>Step 2: Heat released by the unknown metal sample</h3>
We know that, Q = m × c × ΔT
For the unknown metal, ΔT = 101° C - 23.68 °C
= 77.32°C
Assuming the specific heat capacity of the unknown metal is c
Then;
Q = 58.932 g × c × 77.32°C
= 4556.62c Joules
<h3>Step 3: Calculate the specific heat capacity of the unknown metal sample</h3>
- We know that, the heat released by the unknown metal sample is equal to the heat gained by the water.
4556.62c Joules = 506.833 Joules
c = 506.833 ÷4556.62
= 0.111 J/g°C
Thus, the specific heat capacity of the unknown metal is 0.111 J/g°C
45 cm^3 i think? not sure tbh sorry
