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oee [108]
3 years ago
8

The accepted value for the density of a certain material is 3.427 g/ml. Ally 10 points

Chemistry
1 answer:
vivado [14]3 years ago
7 0

Answer:

5.04%

Explanation:

The accepted value of density = 3.427 g/ml

The calculated value of density = 3.600 g/ml

We need to find Ally's percentage error on  her density. The error in any value is given by :

\%=\dfrac{\text{calculated-accepted}}{\text{accepted}}\times 100\\\\=\dfrac{3.427 -3.600 }{3.427 }\times 100\\\\=5.04\%

So, the required error is 5.04%.

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A

Explanation:

A convergent boundary pulls one plate under the other, which can form a rift.

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Wegener attempted to explain the movement of continents but could not identify a source of force strong enough. What did scienti
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6 0
3 years ago
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How many g are equal to 345.7mg?
Mumz [18]

Answer:

0,3457 grams equal to 345.7mg

Explanation:

1000 mg-------1 g

345.7mg------x= (345.7mgx 1 g)/1000mg= <em>0,3457 g</em>

4 0
3 years ago
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For the unbalanced equation, what is the coefficient for c5h10 ?
marshall27 [118]
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8 0
4 years ago
Calculate the cell potential for the following reaction as written at 25.00 °C, given that [Cr2 ] = 0.892 M and [Fe2 ] = 0.0150
Effectus [21]

<u>Given:</u>

Concentration of Cr2+ = 0.892 M

Concentration of Fe2+ = 0.0150 M

<u>To determine:</u>

The cell potential, Ecell

<u>Explanation:</u>

The half cell reactions for the given cell are:

Anode: Oxidation

Cr(s) ↔ Cr2+(aq) + 2e⁻                E⁰ = -0.91 V

Cathode: Reduction

Fe2+ (aq) + 2e⁻ ↔ Fe (s)              E⁰ = -0.44 V

------------------------------------------

Net reaction: Cr(s) + Fe2+(aq) ↔ Cr2+(aq) + Fe(s)

E°cell = E°cathode - E°anode = -0.44 - (-0.91) = 0.47 V

The cell potential can be deduced from the Nernst equation as follows:

Ecell = E°cell - (0.0591/n)log[Cr2+]/[Fe2+]

Here, n = number of electrons = 2

Ecell = 0.47 - 0.0591/2 * log[0.892]/[0.0150] = 0.418 V

Ans: The cell potential is 0.418 V

8 0
3 years ago
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