<h2>
Question
</h2>
A sample of methane collected when the temp was 30 C and 760mmHg measures 398 mL. What would be the volume of the sample at -5 C and 616 mmHg pressure
<h2>
Answer:</h2>
434.32mL
<h2>
Explanation:</h2>
Using the combined gas law:
= k
Where;
P = Pressure
V = Volume
T = Temperature
k = constant.
It can be deduced that:
= 
= k ---------------------(i)
Where:
P₁ and P₂ are the initial and final pressures of the given gas
V₁ and V₂ are the initial and final volumes of the given gas
T₁ and T₂ are the initial and final temperatures of the gas.
<em>From the question:</em>
the gas is methane
P₁ = 760mmHg
P₂ = 616mmHg
V₁ = 398mL
V₂ = ?
T₁ = 30°C = (30 +273)K = 303K
T₂ = -5°C = (-5 +273)K = 268K
Substitute these values into equation (i) as follows;
= 
Solve for V₂
V₂ = 
V₂ = 434.32mL
Therefore, the volume of the sample at -5C and 616mmHg pressure is 434.32mL
Answer:
Explanation:
<u>1) Reactants:</u>
The reactants are:
- <em>Molecular chlorine</em>: this is a gas diatomic molecule, i.e. Cl₂ (g)
- <em>Molecular fluorine</em>: this is also a gas diatomic molecule: F₂ (g)
<u>2) Stoichiometric coefficients:</u>
- <em>One volume of Cl₂ react with three volumes of F₂</em> means that the reaction is represented with coefficients 1 for Cl₂ and 3 for F₂. So, the reactant side of the chemical equation is:
Cl₂ (g) + 3F₂ (g) →
<u>3) Product:</u>
- It is said that the reaction yields <em>two volumes of a gaseous product;</em> then, a mass balance indicates that the two volumes must contain 2 parts of Cl and 6 parts of F. So, one volume must contain 1 part of Cl and 3 parts of F. That is easy to see in the complete chemical equation:
Cl₂ (g) + 3F₂ (g) → 2Cl F₃ (g)
As you see, that last equation si balanced: 2 atoms of Cl and 6 atoms of F on each side, and you conclude that the formula of the product is ClF₃.
The answer is D.sucrose. Sucrose is a disaccharide .
Complete Question:
Theresa creates an experiment where she mixes two red-colored substances together in a container and observes the solution slowly changing from red to blue for the next eight minutes. The solution becomes completely blue after eight minutes. What does this represent about the type of change happening in the container?
Group of answer choices
A. A chemical change started immediately and finished at eight minutes.
B. A non-chemical change started immediately and finished at eight minutes.
C. A chemical change occurred at four minutes.
D. A non-chemical change occurred at four minutes.
Answer:
A. A chemical change started immediately and finished at eight minutes.
Explanation:
A chemical reaction can be defined as the chemical process which typically involves the reaction between two or more chemical elements (substances) to form a new compound, through the rearrangement of the ionic or molecular structure of each chemical element.
This ultimately implies that, a chemical reaction is a chemical change that immediately starts when two or more molecules of a chemical element (substance) known as reactants are combined together to form a new product (compound).
In this scenario, Theresa creates an experiment where she mixes two red-colored substances together in a container and observes the solution slowly changing from red to blue for the next eight minutes. The solution becomes completely blue after eight minutes. Thus, what this represent about the type of change happening in the container is that, a chemical change (from red to blue) started immediately and finished at eight minutes.
Answer:
0; +1; -1
Explanation:
The resonance structure of HN₃ is shown below (you can also use horizontal dashes to represent the bonding pairs).
The molecule has 16 valence electrons, and each N atom has an octet.
To get the formal charges, cut the covalent bonds in half.
Each atom gets the electrons on its side of the cut.
Formal charge = valence electrons in isolated atom - electrons on bonded atom
FC = VE - BE
(a) On Nₐ
VE = 5
BE = 1 lone pair (2)+ 3 bonding electrons = 2 + 3 = 5
FC = 5 - 5 = 0.
(b) On Nb:
VE = 5
BE = 4 bonding electrons = 4
FC = 5 - 4 = +1
(c) On Nc:
VE = 6
BE = 2 lone pairs(4) + 2 bonding electrons = 4 + 2 = 6
FC = 5 - 6 = -1
