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Tema [17]
3 years ago
13

How do i do this? if y’all don’t mind helping lol

Engineering
1 answer:
Nookie1986 [14]3 years ago
7 0
Get a ruler and measure it and for every 1/8 of an inch you multiply by 1 to get your footage
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Routers cannot be used to cut through material.<br><br> True<br> False
mario62 [17]

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Yes a router can be used to cut right through wood and sometimes it makes sense to do so. It leaves nice clean edges, can cut sharp curves and can follow a template

Explanation:

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3 years ago
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For laminar flow over a hot flat plate, the local heat transfer coefficient decreases with distance because (select all that are
kotegsom [21]

Answer:

B. The thickness of the heated region near the plate is increasing.

Explanation:

First we know that, a boundary layer is the layer of fluid in the immediate vicinity of a bounding surface where the effects of viscosity are significant. The fluid is often slower due to the effects of viscosity. Advection i.e the transfer of heat by the flow of liquid becomes less since the flow is slower, thereby the local heat transfer coefficient decreases.

From law of conduction, we observe that heat transfer rate will decrease based on a smaller rate of temperature, the thickness therefore increases while the local heat transfer coefficient decreases with distance.

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4 years ago
What gives thrill in a roller coaster? High speed or Changing acceleration? Explain your answer.
iris [78.8K]

Answer:

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Explanation:

I really hope this helps.

8 0
3 years ago
If increased productivity in the workplace is an example of the macroeconomic impact of the green economy and increased income f
Ivan

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7 0
3 years ago
When the rod is circular, radial lines remain straight and sections perpendicular to the axis do not warp. In this case, the str
Murljashka [212]

The question is incomplete. The complete question is :

The solid rod shown is fixed to a wall, and a torque T = 85N?m is applied to the end of the rod. The diameter of the rod is 46mm .

When the rod is circular, radial lines remain straight and sections perpendicular to the axis do not warp. In this case, the strains vary linearly along radial lines. Within the proportional limit, the stress also varies linearly along radial lines. If point A is located 12 mm from the center of the rod, what is the magnitude of the shear stress at that point?

Solution :

Given data :

Diameter of the rod : 46 mm

Torque, T = 85 Nm

The polar moment of inertia of the shaft is given by :

$J=\frac{\pi}{32}d^4$

$J=\frac{\pi}{32}\times (46)^4$

J = 207.6 mm^4

So the shear stress at point  A is :

$\tau_A =\frac{Tc_A}{J}$

$\tau_A =\frac{85 \times 10^3\times 12 }{207.6}$

$\tau_A = 4913.29 \ MPa$

Therefore, the magnitude of the shear stress at point A is 4913.29 MPa.

3 0
3 years ago
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