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bija089 [108]
3 years ago
14

Calculate the density of a sample of metal that has a mass of 1668 g and takes up a volume of 186.2 cm

Chemistry
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

8,95

Explanation:

Density is equal to mass/volume

D=\frac{m}{v} \\D= \frac{1668g}{186.2} \\D = \frac{8,95g}{cm^3} \\

approximately

Curiosity:

Did you knew that is because of his low density that ships can fluctuate?

Despite their big mass, their volume are far greatter, so the Buoyancy Force acts heavily on them.

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In a chemical reaction, 36 grams of hydrochloric acid reacts with 40 grams of sodium hydroxide to produce sodium chloride and wa
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The answer is <span>The mass of sodium chloride formed is less than 76 grams.
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Remember Mass is never gained or loss in any chemical reactions

So,

hydrochloric acid  + sodium hydroxide  =>  <span>sodium chloride + water
                          Total 76 gram                         Total will also 76 gram

In this case, the mass of sodium chloride will be less than 76 gram because we need to take out the mass of the water.

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3 years ago
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What two atoms are held together by a covalent bond in NaHCO3
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Answer: covalent bond is the force of attraction that holds together two atoms that share a pair of valence electrons. Covalent bonds form only between atoms of nonmetals. The two atoms that are held together in a covalent bond may be atoms of the same element or different elements.

Explanation:

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2 years ago
What is the <br>formula and valency of <br> thiosulphate ​
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3 years ago
What is the term for a push or a pull on an object
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Consider the reaction of peroxydisulfate ion (S2O2−8) with iodide ion (I−) in aqueous solution: S2O2−8(aq)+3I−(aq)→2SO2−4(aq)+I−
kolbaska11 [484]

Answer:

r = 3.61x10^{-6} M/s

Explanation:

The rate of disappearance (r) is given by the multiplication of the concentrations of the reagents, each one raised of the coefficient of the reaction.

r = k.[S2O2^{-8} ]^{x} x [I^{-} ]^{y}

K is the constant of the reaction, and doesn't depends on the concentrations. First, let's find the coefficients x and y. Let's use the first and the second experiments, and lets divide 1º by 2º :

\frac{r1}{r2} = \frac{0.018^{x} x0.036^{y} }{0.027^xx0.036^y}

\frac{2.6x10^{-6}}{3.9x10^{-6}} = (\frac{0.018}{0.027})^xx(\frac{0.036}{0.036})^y

0.67 = 0.67^x

x = 1

Now, to find the coefficient y let's do the same for the experiments 1 and 3:

\frac{r1}{r3} = \frac{0.018x0.036^y}{0.036x0.054^y}

\frac{2.6x10^{-6}}{7.8x10^{-6}} = (\frac{0.018}{0.036})x(\frac{0.036}{0.054})^y

0.33 = 0.5x 0.67^y

0.67 = 0.67^y

y = 1

Now, we need to calculate the constant k in whatever experiment. Using the first :

2.6x10^{-6} = kx0.018x0.036kx6.48x10^{-4} = 2.6x10^{-6}

k = 4.01x10^{-3} M^{-1}s^{-1}[/tex]

Using the data given,

r = 4.01x10^{-3}x1.8x10^{-2}x5.0x10^{-2}

r = 3.61x10^{-6} M/s

7 0
3 years ago
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