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Vladimir79 [104]
3 years ago
8

the length of the glass at 25°C is 500cm after gaining some heat the final length of the glass becomes 500.9cm determine the tem

perature of the glass​
Physics
1 answer:
Vera_Pavlovna [14]3 years ago
8 0
Hi be positive
Smile all day
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A 300.0-kg speedboat is moving across a lake at 35.0 m/s.
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The answer is 300kg times the 35 m/s10,500 kg•m/s
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A 1000-n weight is hanging from a 2.0 m long aluminum rod. A 500-n weight is hanging from a 1.0 m long aluminum rod. The two alu
Hunter-Best [27]

Answer:

Both rod have the same tensile stress

Explanation:

Given information,

The weight first rod, W_{1} = 1000 N

The length of first rod, l_{1} = 2.0 m

The weight second rod, W_{2} = 500 N

The length of second rod, l_{2 = 1.0 m

The equation of tensile stress, σ = \frac{F}{A}

where

σ = tensile stress (N/m^{2} or Pa)

F = Force (N)

A = Area (N/m^{2} or Pa)

so

σ1 =  \frac{W_{1} }{A_{1} }, A = 2πl

    = \frac{1000}{2\pi(2) }

    = \frac{250}{\pi } N/m^{2}

now calculate σ2

σ2 =  \frac{W_{2} }{A_{2} }

     = \frac{500}{2\pi(1) }

     = \frac{250}{\pi } N/m^{2}

σ1/σ2 = \frac{250}{\pi } / \frac{250}{\pi }

σ1/σ2 = 1

σ1 = σ2

Hence, the tensile stress of first and second rod are the same.

5 0
4 years ago
Three objects lie in the x, y plane. Each rotates about the z axis with an angular speed of 5.58 rad/s. The mass m of each objec
QveST [7]

Answer:

a) V1=11.05m/s    V2=92.07m/s     V3=17.24m/s

b) KE = 16238.26J

Explanation:

For tangential speeds:

V1 = \omega*R1=5.58*1.98=11.05m/s

V2 = \omega*R2=5.58*16.5=92.07m/s

V3 = \omega*R3=5.58*3.09=17.24m/s

For the kinetic energy, it can be calculated as:

KE=1/2*\omega^2*(I1+I2+I3)

Where:

I1 = m1*R1^2=5.46*1.98^2=21.4kg.m^2

I2 = m2*R2^2=3.64*16.5^2=990.99kg.m^2

I3 = m3*R3^2=3.21*3.09^2=30.65kg.m^2

So,

KE=1/2*5.58^2*(21.4+990.99+30.65)

KE=16238.26J

4 0
3 years ago
What forces do a free body diagram analyze?
Bogdan [553]

Friction, gravity, normal force, drag force, tension force and human force are the forces that occurs on free body.

<h3>What are the forces in a free body diagram?</h3>

There are large number of external forces acting on an object such as friction, gravity, normal force, drag force, tension force and human force due to pushing or pulling. These forces can cause the motion of the free body which is present at rest form or can stop a body which is moving. A free-body diagram is a useful means of describing and analyzing all the forces that act on a body to determine equilibrium.

So we can conclude that friction, gravity, normal force, drag force, tension force and human force are the forces that occurs on free body.

Learn more about force here: brainly.com/question/388851

#SPJ1

5 0
2 years ago
Al convertir 12 Dlt / min a Lt / s, obtenemos:
Evgen [1.6K]
Answer
It’s D I think
7 0
3 years ago
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