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tamaranim1 [39]
3 years ago
15

Camera lenses are described in terms of

Physics
1 answer:
Lesechka [4]3 years ago
6 0

Answer:

The position of the image from the camera lens is approximately 121.1 mm

Explanation:

The given parameters of the lens are;

The specification of the camera lens = 120 mm

Therefore, the focal length of the camera lens, f = 120 mm = 0.12 m

The distance of the object from the camera, d_o = 13 m

The lens equation for finding the position of the image is given as follows;

\dfrac{1}{f} = \dfrac{1}{d_o} + \dfrac{1}{d_i}

Where;

d_i = The position of the image from the camera lens

Therefore, by plugging in the known values, we have;

\dfrac{1}{13} = \dfrac{1}{0.12} + \dfrac{1}{d_i}

\dfrac{1}{d_i}  = \dfrac{1}{0.12} -  \dfrac{1}{13} = \dfrac{13 - 0.12}{0.12 \times 13} = \dfrac{12.88}{1.56} = \dfrac{322}{39}

\therefore d_i = \dfrac{39}{322}  \approx  0.1211

The position of the image from the camera lens, d_i = 0.1211 m = 121.1 mm

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4 0
3 years ago
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If the pitched ball was traveling 77 mph before stanton's bat hit it and 120 mph after his bat hit it, by what amount did the sp
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here we will use the concept of Newton's III law

as per Newton's III law the impulse given to the ball is same as the impulse lost by the bat

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