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When base is added in order to increase the pH of a solution, it results in MOH salt <u>precipitating first.</u>
Equation :
MOH (s) ⇄ M⁺ (aq) ₊ OH⁻(aq)
K = [M⁺] [OH⁻]
K = 1.39×10⁻¹² and [M⁺] = 0.001M
∴ 1.39×10⁻¹² = (0.001M) [OH⁻]
[OH⁻] = 1.004×10⁻¹⁹M
pOH = -log [OH⁻] = 11.9
pH = 14 - pOH
= 14 - 11.9
<u>pH = 2.1</u>
To learn more about solubility equilibrium ;
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Answer:
Explanation:
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In this case, we can compute the percent composition of chlorine as shown below:
Whereas the atomic mass of chlorine is 35.45 g/mol and the molar mass of C₂H₂Cl₂ is 96.95 g/mol, thus, the percent composition turns out:
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