Answer:
[NaCl(aq)] = 0.25M
Explanation:
Molarity = moles solute / volume of solution in liters
moles NaCl in 29.25 grams = 29.25g/58g·mol⁻¹ = 0.5043 mole
Molarity = 0.5043 mole NaCl / 2 Liters = 0.2555M ≅ 0.25M (2 sig-figs)
First, let us calculate the moles of solute or sodium
bicarbonate is in the 1 ml solution.
<span>moles = 1 mL * (1 g
/ 9 mL) = 0.11 moles</span>
The molar mass of sodium bicarbonate is 84 g/mol,
therefore the mass is:
mass = 0.11 moles * 84 g/mol
<span>mass = 9.33 g</span>