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JulijaS [17]
2 years ago
7

A 150 j of energy is added to a system that does 50 j of work is done. By how much wiull the internal energy of the system be ra

ised?
Chemistry
2 answers:
Alex73 [517]2 years ago
8 0

Answer:

<h2>3 internal energy</h2>

Explanation:

{hope it helps}}

madam [21]2 years ago
6 0

Answer:

thnx for the points too muchee

Explanation:

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4. By what quantity must the heat capacity be divided to obtain the specific heat of that material? (I poin
charle [14.2K]

Answer:

its mass

its temperature

Explanation:

The heat capacity of a body is the amount of heat needed to raise that temperature of a body by 1k or 1°C.

It is expresses as:

              H = m c Ф

where m is the mass of the body

           c is the specific heat of the body

           Ф is the temperature change of the body

Specific heat capacity is that heat content needed to raise the temperature of a unit mass of a substance by 1k or 1°C

Heat capacity is also known as heat content;

 To solve the problem:

 since H = m c Ф

  we make the unknown c the subject of the expression;

                c = \frac{H}{m (t_{2} - t_{1} )} = H / mФ

So to obtain the specific heat capacity, divided the heat capacity by mass and its temperature change.

8 0
3 years ago
What is the correct name for ionic compound Cs2S?
Leno4ka [110]
The name for the ionic compound Cs2S is Cesium sulfide.
7 0
3 years ago
The following equation is one way to prepare oxygen in a lab. 2KClO3 → 2KCl + 3O2 Molar mass Info: MM O2 = 32 g/mol MM KCl = 74
Alex73 [517]
From  the  equation  above   the  reacting   ratio  of  KClO3   to  O2  is  2:3 therefore  the  number  of  moles  of  oxygen  produced  is  ( 4 x3)/2 =  6 moles  since   four  moles  of  KClO3  was  consumed
mass=relative  formula mass  x  number  of  moles
That  is   32g/mol x 6  moles  =192grams


8 0
3 years ago
Read 2 more answers
SCIENCE QUEASTION I PUTED IT IN CHEMISTRY BECAUSE BRAINLY HAS NO SCIENCE WILL MARK BRAINLIEST
Elena L [17]

#1. The condition of the atmosphere at a certain time and certain place

#2. The rate of evaporation is EQUAL to the rate of condensation

Please mark Brainliest if this was helpful! :)

7 0
3 years ago
A certain ore is 37.3% nickel by mass how many kilograms of this ore would you need to dig up to have 10.0g of nickel
jeka57 [31]
If the grade of the ore is 37.3% nickel, then the unknown quantity to get 10 grams of nickel is 0.373 x = 10 grams or x = 10/0.373=26.8 grams or 0.0268 kg needed to dig up to recover the 10 grams of nickel. At this grade of ore, 1 kilogram would yield 373 grams of nickel. 
7 0
3 years ago
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