Ask question

Ask question

All categories

3 years ago

7

A 150 j of energy is added to a system that does 50 j of work is done. By how much wiull the internal energy of the system be ra

ised?

2 answers:

Alex73 [517]3 years ago

8 0

Answer:

<h2>3 internal energy</h2>

Explanation:

${hope it helps}}$

madam [21]3 years ago

6 0

Answer:

thnx for the points too muchee

Explanation:

You might be interested in

I need help with this

masha68 [24]

Answer is —-7373/63)3

6 0

2 years ago

_______ and _______ are located in the nucleus of the atom, while _______ exist in areas of probability around the nucleus.

Reika [66]

The correct answer would be C.

6 0

3 years ago

How do you balance hgo ?

Marina CMI [18]

What are you asking? Id love to help but cant without proper information

8 0

3 years ago

what does a set of four quantum numbers tell you about an electron. compare and contrast the locations and properties of two ele

daser333 [38]

Look on ///// quizlet.com

7 0

3 years ago

An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?

umka2103 [35]

<u>Answer:</u> The boiling point of solution is 100.53

<u>Explanation:</u>

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

Or,

$\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

$K_b$ = molal boiling point elevation constant = 0.51°C/m

$m_{solute}$ = Given mass of solute (CsCl) = 8.00 g

$M_{solute}$ = Molar mass of solute (CsCl) = 168.4 g/mol

$W_{solvent}$ = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

$\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC$

Hence, the boiling point of solution is 100.53

6 0

3 years ago