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dexar [7]
3 years ago
15

PLEASE HELP ASAP BEST ANSWER WILL BE MARKED BRAINLIEST

Physics
1 answer:
Mademuasel [1]3 years ago
8 0

Answer:

water

I hope this helps :)

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How many molecules are in 3 moles of CO2
mote1985 [20]

Answer:

There are 1.806 X 1024 molecules in 3 moles of CO2. This concept is similar to counting 144 eggs and dividing by 12 to get the number of cartons.

8 0
3 years ago
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Why is Sean Carrol studying the fruit fly?
andrew11 [14]

Answer:

Carroll has spent his career studying how evolution occurs at the genetic level, pinpointing many of the molecular changes that lead to new traits and new species. Most of Carroll's discoveries have come to light by studying the common fruit fly Drosophila melanogaster, the workhorse of modern molecular genetics.

Have a great day!

3 0
3 years ago
Two ice skaters, Lilly and John, face each other while at rest, and then push against each other's hands. The mass of John is tw
seropon [69]

Answer:

Lilly's speed is two times John's speed.

Explanation:

m = Mass

a = Acceleration

t = Time taken

u = Initial velocity

v = Final velocity

The force they apply on each other will be equal

F=ma\\\Rightarrow a_l=\frac{F}{m_l}

F=ma\\\Rightarrow a_j=\frac{F}{2m_l}\\\Rightarrow a_j=\frac{1}{2}a_l

v=u+at\\\Rightarrow v_l=0+\frac{F}{m_l}\times t\\\Rightarrow v_l=a_lt

v=u+at\\\Rightarrow v_l=0+\frac{F}{2m_l}\times t\\\Rightarrow v_j=\frac{1}{2}a_lt\\\Rightarrow v_j=\frac{1}{2}v_l\\\Rightarrow v_l=2v_j

Hence, Lilly's speed is two times John's speed.

4 0
3 years ago
What is the force in N of an object that has a mass of 7 kilograms and an acceleration of 4 m/s/s
VMariaS [17]

Newton's 2nd law of motion:         Force = (mass) x (acceleration)

If you want to move a 7-kg object with an acceleration of 4 m/s²,
then you will need to push it with (7 x 4) = 28 newtons of force.

4 0
3 years ago
Ask Your Teacher When a potential difference of 160 V is applied to the plates of a parallel-plate capacitor, the plates carry a
Morgarella [4.7K]

The spacing between the plates is 5.4\cdot 10^{-6} m

Explanation:

The electric field in the spacing between the plates of a parallel-plate capacitor is uniform and it is given by

E=\frac{\sigma}{\epsilon_0}

where

\sigma is the surface charge density

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the vacuum permittivity

We also know that the relationship between electric field and potential difference across a parallel-plate capacitor is

V=Ed

where

V is the potential difference

d is the spacing between the plates

Combining the two equations we get

V=\frac{\sigma d}{\epsilon_0}

And given that here we have:

V = 160 V

\sigma = 26.0 nC/cm^2 = 26.0\cdot 10^{-9} C/cm^2=26.0\cdot 10^{-5} C/m^2

We can solve the equation for d, the spacing between the plates:

d=\frac{V \epsilon_0}{\sigma}=\frac{(160)(8.85\cdot 10^{-12})}{26.0\cdot 10^{-5}}=5.4\cdot 10^{-6} m

Learn more about capacitors:

brainly.com/question/10427437

brainly.com/question/8892837

brainly.com/question/9617400

#LearnwithBrainly

7 0
4 years ago
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