Given that the function of the wave is f(x) = cos(π•t/2), we have;
a. The graph of the function is attached
b. 4 units of time
c. Even
d. 4.935 J/kg
e. 1.234 W/kg
<h3>How can the factors of the wave be found?</h3>
a. Please find attached the graph of the signal created with GeoGebra
b. The period of the signal, T = 2•π/(π/2) = <u>4</u>
c. The signal is <u>even</u>, given that it is symmetrical about the y-axis
d. The energy of the signal is given by the formula;

Which gives;
E = 0.5 × 1.571² × 1² × 4 = <u>4.935 J/kg</u>
e. The power of the wave is given by the formula;
E = 0.5 × 1.571² × 1² × 4 × 0.25 = <u>1.234 W/</u><u>kg</u>
Learn more about waves here:
brainly.com/question/14015797
B. Elastic potential to kinetic energy
The elastic potential energy in the slingshot will be transferred to the stone as kinetic energy as the stone is launched.
Answer:
0.74 m/s
Explanation:
From the question,
We apply the law of conservation of momentum,
Total momentum before collision = Total momentum after collision.
Since the skateboard, the person and the brick where stationary, therefore, the total momentum before collision is 0
0 = Total momentum after collision
(m+M)V + m'v = 0
Where m = mass of the skateboard, M = mass of the person, m' = mass of the brick, V = recoil velocity of the person and the skateboard, v = velocity of the brick
make V the subject of the equation above
V = -m'v/(m+M)................... Equation 1
Given: m = 4.10 kg, M = 68.0 kg, m' = 2.50 kg, v = 21.0 m/s.
Substitute these values into equation 1
V = -(2.5×21)/(68+2.5)
V = 52.50/70.5
V = 0.74 m/s
Answer:
mass = 9.7 kg
Explanation:
As we know that when object is at rest on the ground of flat base then we will have

so from here

now we have
N = 95 Newton
now from above equation we will have



Answer:
7. free fall -- h. 9.8m/s^2
3. Velocity -- x. 60 km/hr west
6. Acceleration -- d. change in velocity/time
8. Centrifugal -- s. towards the centre
13. Work done --w. Force * displacement
5. Uniform circular motion --j. spin cycle in washer
18. Power -- r. kW an hour
7. g -- a. 10N
hope this helps