Deduce a value for the latent heat of evaporation Lv of water. State clearly any simplifying assumptions that you make. Estimate
the pressure at which ice and water are in equilibrium at −2◦C given that ice cubes float with 4/5 of their volume submerged in water at the triple point (0.01◦C, 612Pa). [Latent heat of sublimation of ice at the triple point, Ls = 2776 °´ 103 Jkg−1.]
2 answers:
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Answer:
Explanation:
We are given that
Diameter of wire=d=4.12 mm
Radius of wire=r
Current=I=8 A
Drift velocity=
We have to find the density of free electrons in the metal
We know that
Density of electron=
Using the formula
Density of free electrons=
By using Area of wire=
Density of free electrons=
Answer:
Electric field, E = 45.19 N/C
Explanation:
It is given that,
Surface charge density of first surface,
Surface charge density of second surface,
The electric field at a point between the two surfaces is given by :
E = 45.19 N/C
So, the magnitude of the electric field at a point between the two surfaces is 45.19 N/C. Hence, this is the required solution.