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Goryan [66]
3 years ago
15

Teachers are interested in knowing what study techniques their students are utilizing. The researchers randomly select every 10t

h student that walks into class.
Simple Random Sample (SRS)

Stratified Sample

O Systematic Sample

O Cluster Sample​
Physics
1 answer:
uranmaximum [27]3 years ago
5 0

Answer:

Simple Random Sample (SRS)

Explanation:

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Explanation:

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3 years ago
Which law of motion accounts for the following statement?
strojnjashka [21]
I know that its not the second law. I'm almost positive its the first one. Please let me know if I'm wrong. This sentence makes no sense when you put it with the third law. So, the first law is my guess...
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3 years ago
Read 2 more answers
What is the speed of sound at 33 °C (m/s)? For a frequency of 5 kHz, how large do you expect the wavelength to be (m)?
Vedmedyk [2.9K]

Answer:

-The speed of sound at 33°C is 362.8 m/s.

-The wavelength at a frequency at 5 kHz is 0.07256 m .

Explanation:

let v = 343 m/s be the speed of sound.

let T be the temperature.

then the speed of sound V, at 33°C is given by:

V = v + 0.6×T

   = 343 + 0.6×33

   = 362.8 m/s

Therefore, the speed of sound at 33°C is 362.8 m/s.

the wavelength at a frequency of f = 5kHz = 5000 Hz is given by:

λ = V/f

  = (362.8)/(5000)

  = 0.07256 m

Therefore, the wavelength at a frequency at 5 kHz is 0.07256 m .

7 0
3 years ago
Why do we learn useless nonsense school, why don't we learn what we will actually use in life
laila [671]
I totally agree but, in my opinion its because of the government and what the state has control over. Teacher have little control over it.
4 0
3 years ago
A Nichrome wire 44 cm long and 0.30 mm in diameter is connected to a 3.1 V flashlight battery. What is the electric field inside
Alexeev081 [22]

Answer:

7.05 Volts/m

Explanation:

L = length of the Nichrome wire = 44 cm = 0.44 m

V = Potential difference across the end of the wire = battery voltage = 3.1 Volts

E = magnitude of electric field inside the wire

Magnitude of electric field inside the wire is given as

E = \frac{V}{L}

Inserting the values

E = \frac{3.1}{0.44}

E = 7.05 Volts/m

4 0
3 years ago
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