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exis [7]
3 years ago
6

Identify the slope-intercept form and the graph of the line described by the equation 2x−y=0.

Mathematics
2 answers:
Arlecino [84]3 years ago
8 0

Answer:

y = 2x

Step-by-step explanation:

In order to get from standard form to slope-intercept form (y = mx + b), we have to find what we are looking for.  Since we want to get slope-intercept form, we want to find y.  To find y, we isolate it.

2x - y = 0

Subtract 2x from both sides...

(2x - 2x) - y = (0 - 2x)

Now we have - y = -2x + 0.

But wait, we can't have a negative y... so we simply divide by -1.

(-y/-1) = (-2x/-1) + (0/-1).

Since 0 divided by any number is just zero, we can drop it.  Now that y is positive, we have our answer!

vitfil [10]3 years ago
7 0

Answer: y=2x

Step-by-step explanation:

Let's solve for y.

Step 1: Add -2x to both sides.

2x−y+−2x=0+−2x

−y=−2x

Step 2: Divide both sides by -1.

-y/-1 = -2x.-1

y=2x

Therefore, the y=mx+b form of this question would be y=2x

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X^2=-36 how do I solve this
OLEGan [10]

Hey!

---------------------------

Answer:

No Real Solutions.

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Explanation:

Well, because you would typically find the square root of -36 but there is no real solution that would equal -36. If it was x^2 = 36 it would be a totally different thing.

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Hope This Helped! Good Luck!

4 0
3 years ago
Pleaser answer CORRECTLY , WILL MARK BRAINLIEST !!!!!!!!!
Nataly [62]

Answer:

Step-by-step explanation:

-3a + 6b = a + 4b

-4a + 6b = 4b

-4a = -2b

a = -2b/-4

f(a) = -b/2

5 0
3 years ago
9. Write an algebraic expression for each verbal expression.
alexandr402 [8]
A) x+6
B)3x
C)x/7
D)4-5x
E)x^2-2
F)2X+16
4 0
2 years ago
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The heights of a certain type of tree are approximately normally distributed with a mean height p = 5 ft and a standard
arsen [322]

Answer:

A tree with a height of 6.2 ft is 3 standard deviations above the mean

Step-by-step explanation:

⇒ 1^s^t statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)

an X value is found Z standard deviations from the mean mu if:

\frac{X-\mu}{\sigma} = Z

In this case we have:  \mu=5\ ft\sigma=0.4\ ft

We have four different values of X and we must calculate the Z-score for each

For X =5.4\ ft

Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.4-5}{0.4}=1

Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.

⇒2^n^d statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean. (FALSE)

For X =4.6 ft  

Z=\frac{X-\mu}{\sigma}\\Z=\frac{4.6-5}{0.4}=-1

Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean .

⇒3^r^d statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean (FALSE)

For X =5.8 ft

Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.8-5}{0.4}=2

Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.

⇒4^t^h statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean. (TRUE)

For X =6.2\ ft

Z=\frac{X-\mu}{\sigma}\\Z=\frac{6.2-5}{0.4}=3

Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.

6 0
3 years ago
What's five divided by two
bogdanovich [222]
The answer to this problem would be 2.5.
4 0
3 years ago
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