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3 years ago

6

Which type of hazard results in water pollution? A) Biological hazard B) Chemical hazard C) Physical hazard D) Environmental haz

ard

2 answers:

Eduardwww [97]3 years ago

7 0

Answer:

(a). biological pollution

makvit [3.9K]3 years ago

7 0

Answer:

B.

Explanation:

Chemicals are the most common water contaminants. They effect both surface and underground water bodies.

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To solve the problem, make assumptions for missing data and justify. Given:

finlep [7]

Answer:

5,4,1, this is a explication

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2 years ago

What is the primary responsibility of ABET?

nalin [4]

Answer:

C

Explanation:

The ABET (Accreditation Board for Engineering and Technology) is a non-governmental organization that accredits programs in applied science, computing, engineering, and engineering technology, both in the United States and elsewhere.

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3 years ago

What are two ways you can see that there is a smaller load going to the base of the transistor?

Lyrx [107]

Answer:

<h3><em>Transistor switches can be used to switch a low voltage DC device (e.g. LED’s) ON or OFF by using a transistor in its saturated or cut-off </em><em>state</em></h3>

<em>. Cut-off </em><em>Region</em>

<em>Here the operating conditions of the transistor are zero input base current ( IB ), zero output collector current ( IC ) and maximum collector voltage ( VCE ) which results in a large depletion layer and no current flowing through the device. Therefore the transistor is switched “Fully-OFF”.</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>2</em><em>.</em><em>Saturation </em><em>Region</em>

<em>Here the transistor will be biased so that the maximum amount of base current is applied, resulting in maximum collector current resulting in the minimum collector emitter voltage drop which results in the depletion layer being as small as possible and maximum current flowing through the transistor. Therefore the transistor is switched “Fully-ON”.</em>

Explanation:

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7 0

2 years ago

A liquid propellant engine has the following characteristics: chamber pressure of 7 MPa, constant ratio of specific heats of 1.3

Cloud [144]

Answer:

1.55
260 N.s
3370 m
1.6
43.75 kg/s

Explanation:

1) Thrust coefficient at sea level.

Cfsl = TSL / Pca

TSL = Mp * Vc + ( Pc - Pa )Ac

Mp = mass flux = 43.75 kg/s

∴ Cfsl = Mp Vc / Pca + ( Pc - Pa )/Pc * ( Ac / A* )

= 1.6 - 0.04923 = 1.55

<u>2) Specific impulse at sea </u>

Isp = Vc / g = 2549.75 / 9.81

= 260 N.s

3) Altitude at optimal expansion

H = 3370 m

<u>4) thrust coefficient at optimal expansion </u>

CF = 1.6

attached below is the detailed solution

<u>5) Mass flux through the throat </u>

Mass flux = P1 * At / Cc

= ( 7*10^6 * 0.01 ) / 1600

= 43.75 kg/s

8 0

3 years ago

A peripheral milling operation is performed on the top surface of a rectangular workpart which is 400 mm long and 60 mm wide. Th

oee [108]

Answer:

N = 278.5 rpm

F = 348.15 mm/min

machine time = 10.34 seconds

material removal rate = 33420000 mm³/min

Explanation:

given data

length L = 400 mm

width W = 60 mm

diameter D = 80 mm

no of cutting n = 5

velocity V = 70 m/min = 70000 mm/min

chip load P = 0.25 mm/tooth

depth = 5 mm

solution

we know velocity that is express as

velocity V = $\pi$ D N ........1

N = $\frac{70000}{\pi \times 80}$

N = 278.5 rpm

and

now we get feed rate in milling operation is

F n P N

F = 5 × 0.25 × 278.5

F = 348.15 mm/min

and

now we get actual machine time to make 1 pass across surface of worl is

machine time = $\frac{W}{F}$

machine time = $\frac{60}{348.15}$

machine time = 0.1723 min = 10.34 seconds

and

max material removal rate during these cut is

material removal rate = A × d × N

material removal rate = 400 × 60 × 5 × 278.5

material removal rate = 33420000 mm³/min

7 0

3 years ago