Answer:
clear, clc
prob3_5([1,2,3],[6,5,7],12,11,22,55,76)
function T=prob3_5(x,y,N,L,W,T1,T2)
w=zeros(1,length(x));
for n=1:2:N
for i=1:length(x)
w(i)=w(i)+(2/pi)*(2/n)*sin(n*pi*x(i)/L).*sinh(n*pi*y(i)/L)/sinh(n*pi*W/L);
end
end
T=(T2-T1)*w+T1;
end
Explanation:
Please input the commands into MATLAB
Answer:
639.4psi
Explanation:
Pressure at the closed valve = Air pressure+ (density*gravity*height)
=23psi+(49.27lb/ft^3*32.17ft/s^2*56ft^3)
=23psi+88760.89psft
=23psi+(88760.89/144)psi
=23+616.4
=639.4psi
Answer:
Normal force = 0.326N
Explanation:
Given that:
mass released from rest at C = 3.7 g = 3.7 × 10⁻³ kg
height of the mass = 1.1 m
radius = 0.2 m
acceleration due to gravity = 9.8 m/s²
We are to determine the normal force pressing on the track at A.
To to that;
Let consider the conservation of energy relation; which says:
mgh = mgr + 1/2 mv²
gh = gr + 1/2 v²
gh - gr = 1/2v²
g(h-r) = 1/2v²
v² = 2g(h-r)
However; the normal force will result to a centripetal force; as such, using the relation
N =mv²/r
replacing the value for v² = 2g(h-r) in the above relation; we have:
Normal force = 2mg(h-r)/r
Normal force = 2 × 3.7 × 10⁻³ × 9.8 ( 1.1 - 0.2 )/ 0.2
Normal force = 0.065268/0.2
Normal force = 0.32634 N
Normal force = 0.326N
The rainfall run off model HEC-HMS is combined with river routing model. They are used for simulating the rainfall process.
Explanation:
The HEC - HMS rainfall model is used for simulating the rainfall runoff process. In this study the soil conservation service and curve number method is used to calculate the sub basin loss in basin module.
It provides various options for providing the rainfall distributions in the basin. It has the control specification module used to control the time interval for the simulations.
The one dimensional continuity equation is
бA / бT + бQ / бx= 0
