The approximate amount of water that remains in the tub after the 6 spherical balls are placed in the tub are 3479.12 in³.
<h3>What is the approximate amount of water that remains in the tub?</h3>
The first step is to determine the volume of the cylinder.
Volume of the tub = πr²h
Where:
- r = radius = diameter / 2 = 18/2 = 9 inches
- h = height
- π = 3.14
3.14 x 9² x 20 = 5086.8 in³
The second step is to determine the volume of the 6 balls.
Volume of a sphere= 4/3πr³
r = diameter / 2 = 8/2 = 4 inches
6 x (3.14 x 4/3 x 4³) = 1607.68 in³
Volume that remains in the tub = 5086.8 in³ - 1607.68 in³ = 3479.12 in³
To learn more about the volume of a sphere, please check: brainly.com/question/13705125
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Volume of a cone = <span>πr^2(h/3)
r=6
h=27
v = </span><span>π(6^2)27/3
v = </span><span>π (36)(9)
v=</span><span>π324 in. cubed
or
v=1,017.36 in. cubed </span>
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Step-by-step explanation:
36:90 in simplest form would be
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